HTML to PHP dropdown menu

Question

I have this html part for a dropdown menu:

<form name="navList" onsubmit="return submitForm();">
<select name="subMenu">
<option value> </option>
<option value> CR_ID </option>
<option value> CR_HEADLINE </option>
<option value> CRI_CLOSEDATE </option>
<option value> CRI_ASSIGNEE </option>
</select>

How can I change this into php, using this function?

foreach($array as $key=>$value)
{
$html .= "<option value='$key'>$value</key>";
}
echo "<select name="process">$html</select>";

"<option value='$key'>$value</key>" - you open option tag, but then close key; however, I don't see a question here. — Tommi
– Tommi, Commented Jul 12, 2013 at 11:12

Roopendra · Accepted Answer · 2013-07-12 12:26:01Z

2

You forget to add escape sequences in your output . Please refer this demonstration:-

$optionArray = array(
            0 => 'CR_ID',1=> 'CR_HEADLINE',
            2 => 'CRI_CLOSEDATE',3 => 'CRI_ASSIGNEE'
            );
foreach($optionArray as $key=>$value)
{
$html .= "<option value='$key'>$value</key>";
}
echo "<select name=\"process\">".$html."</select>";

OR

    echo '<select name="process">'.$html.'</select>';

edited Jul 12, 2013 at 12:26

answered Jul 12, 2013 at 11:15

Roopendra

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Comments

Tro · Accepted Answer · 2013-07-12 11:12:40Z

0

echo "<select name=\"process\">".$html."</select>";

You needed to escape your quotes.

answered Jul 12, 2013 at 11:12

Tro

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Comments

swapnesh · Accepted Answer · 2013-07-12 11:23:29Z

0

<?php

$html ='';
$myArray = array(0 => '',1 => 'CR_ID',2=> 'CR_HEADLINE', 3 => 'CRI_CLOSEDATE',4 => 'CRI_ASSIGNEE');

foreach($myArray as $key=>$value)
{
    $html .= "<option value='$key'>$value</key>";
}

echo "<select name=\"process\">".$html."</select>";

Link - http://codepad.viper-7.com/YpccFw

edited Jul 12, 2013 at 11:23

answered Jul 12, 2013 at 11:18

swapnesh

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