Validation In java script

Question

Currently I'm attempting to create a regular expression to validate an user input field which requires the input to contain at least one of each of the following:

an upper-case character
a digit
one of the following special characters: & @ ! # +

I attempted to create a regular expression that will validate the input correctly:

/^([a-zA-Z+]+[0-9+]+[&@!#+]+)$/i.test(userpass);

However, the input is not validated correctly. How should I go about doing that?

Your regexp requires that all the letters come first, then all the numbers, then all the special characters. Also, you allow + in each of those groups, why? — Barmar
– Barmar, Commented Jul 2, 2013 at 6:16
@Qantas94Heavy - the list of special characters is in the OP's regex. Reading between the lines I think they want the test string to contain at least one of those "special" characters, at least one letter, and at least one digit, in any order - but that regex enforces a specific order as per Barmar's comment. — nnnnnn
– nnnnnn, Commented Jul 2, 2013 at 6:30

Barmar · Accepted Answer · 2013-07-02 06:17:49Z

1

Try this:

/[a-z]/i.test(userpass) && /[0-9]/.test(userpass) && /[&@!#+]/.test(userpass)

answered Jul 2, 2013 at 6:17

Barmar

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Anirudha · Accepted Answer · 2013-07-02 06:28:24Z

1

you can simplify the regex with lookahead

 ^(?=.*[&@!#+])(?=.*[A-Z])(?=.*\d).+$
  ------------- --------- -------
      |        |         |->match only if there's a digit ahead
      |        |->match only if there's a uppercase alphabet ahead
      |->match only if there's any 1 of [&@!#+]

[A-Z] would match a single uppercase letter

\d would match a single digit

OR use search

if(input.search(/\d/)!=-1 && input.search(/[&@!#+]/)!=-1) && input.search(/[A-Z]/)!=-1)

edited Jul 2, 2013 at 6:28

answered Jul 2, 2013 at 6:22

Anirudha

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