Python creating an array from hex bytes

Question

I have the following string:

"0c a8 f0 d6 02 00 00 00 00 d0 1c d1 10 d2 00 d3 00 d7 01 d4 78 20 ff"

As you can see, it contains hex values and I want to transform it into an array of bytes, using Python 2.4.4 (NOT 3.x, so I don't have the useful bytearray). The only way to achieve it as per my knowledge is something like:

i = []
i.append(0x0c)
i.append(0xa8)
i.append(0xf0) # ... and so on
.....
z = ''.join(chr(c) for c in i)

But this is horrible. Any good hint how to solve this efficiently?

clyfish · Accepted Answer · 2013-06-27 07:58:23Z

3

'0c a8 f0 d6 02 00 00 00 00 d0 1c d1 10 d2 00 d3 00 d7 01 d4 78 20 ff'.replace(' ', '').decode('hex')

answered Jun 27, 2013 at 7:58

clyfish

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1 Comment

Daemon Painter Aug 29 at 15:04

not for python 3

oleg · Accepted Answer · 2013-06-27 08:16:36Z

1

You can decode string replacing all whitespaces

s = "0c a8 f0 d6 02 00 00 00 00 d0 1c d1 10 d2 00 d3 00 d7 01 d4 78 20 ff"
x = s.replace(" ", "").decode('hex')

or You can use generator statement for example

x = ''.join(chr(int(i, 16)) for i in  s.split())

answered Jun 27, 2013 at 8:16

oleg

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