put pointer values in a array

Question

I have the following part of the code:

         i = 0;
         while (ptr != NULL)
         {
          if (i == 0)
             strcat(machine, ptr); 
          if (i == 2)
             strcat(number, ptr);
          if (i == 4)
             strcat(hr, ptr); 
          if (i == 6)
             strcat(dw, ptr); 
          if (i == 8)
             strcat(vcc, ptr);
          i++;
         }
         printf("Final: %s, %s, %s, %s, %s\n", machine, number, hr, dw, vcc);

And i have these results:

Final: 3, 34, 56, 67, 56

How can I save them in a 10 position array in the positions 5-9? To be like that:

0 0 0 0 0 3 34 56 67 56

I wrote the following code but it is uncompleted because I do not know how to pass &machine, &number, &hr, &dw, &vcc in the table

FILE *ft = fopen("Desktop/mytext.txt","a+");
struct tm *tp;
time_t t;
char s[80];

t = time(NULL);
tp = localtime(&t);
strftime(s, 80, "%d/%m/%Y  %H:%M:%S", tp);
char table1[1][10];
for(int i = 0; i<1; i++)
{
    fprintf(ft,"%s ",s);
    for(int j = 0; j<10; j++)
    fprintf(ft,"%d ",table1[i][j]);
}

Hey your Question is not clear?

Apoorva sahay
– Apoorva sahay

2013-06-20 12:21:27 +00:00
Commented Jun 20, 2013 at 12:21 — Apoorva sahay
– Apoorva sahay, Commented Jun 20, 2013 at 12:21

Alexis · Accepted Answer · 2013-06-20 13:10:54Z

2

Let's say you have already your values into "machine, number, hr, dw, vcc" (who are char*)

You can't store them into your char table1[1][10] because it's a table of array who can contain only one array of 10 char.

so you neeed a char ** looking like:

char *table1[10] = {0};

table1[5] = machine; 
table1[6] = number;
table1[7] = hr; 
table1[8] = dw; 
table1[9] = vcc;

but to display it you are going to get few problems but you can always do something like:

for (int i = 0; i < 10; i++)
{
 if (table1[i] == NULL)
   printf("0 ");
else
   printf("%s ", table1[i]);
}
printf("\n");

But in your case why you don't simply use a int[10] ?

edited Jun 20, 2013 at 13:10

answered Jun 20, 2013 at 12:21

Alexis

2,1792 gold badges25 silver badges39 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Dayal rai · Accepted Answer · 2013-06-20 12:20:01Z

0

It is not clear what exactly you want but just giving a shot

char table1[1][10]={0};    
    table1[0][5]= machine;
    table1[0][6]=number;
    table1[0][7]=hr;
    table1[0][8]=dw;
    table1[0][9]=vcc;

answered Jun 20, 2013 at 12:20

Dayal rai

6,63624 silver badges29 bronze badges

Comments

tike · Accepted Answer · 2013-06-27 08:36:02Z

0

given that you are able to manipulate the first piece of code, a possible way would be:

   i = 0;
   int offset = 5;
   char* table[1][10];       

   while (ptr != NULL)
     {
      if (i == 0)
         strcat(machine, ptr);
      if (i == 2)
         strcat(number, ptr);
      if (i == 4)
         strcat(hr, ptr); 
      if (i == 6)
         strcat(dw, ptr); 
      if (i == 8)
         strcat(vcc, ptr);
      table[0][5+(i/2)] = ptr;   
      i++;
     }
  printf("Final: %s, %s, %s, %s, %s\n", machine, number, hr, dw, vcc);

in the second piece of code I would get rid of the outer for loop and just write:

   for(int j = 0; j<10; j++)
      fprintf(ft,"%d ",table1[0][j]);

given that you do really have only one such array as your declaration suggests.

please note, that the above solution would only work locally within the function, since returning local variables doesn't work. In order to be able to globally use the table structure, you might want to malloc() and strcpy() the values into the array.

edited Jun 27, 2013 at 8:36

answered Jun 20, 2013 at 12:20

tike

2,29419 silver badges20 bronze badges

5 Comments

dali1985 Over a year ago

I am trying to use your solution but (as I forgot to mention) I have declared char* ptr; so I have an error in the 'table' line 'invalid conversion from 'char*' to 'char''

dali1985 Over a year ago

ok I changed the table[i][5+(i/2)]= *ptr but now I have a segmentation fault

tike Over a year ago

Looking at it again, there is an obvious error here: table[i][5+(i/2)] = ptr, should really be table[0][5+(i/2)] = *ptr. My apologies.

dali1985 Over a year ago

No I think the problem for the segmentation fault is the declaration of i. I think it exceeds the array dimensions.

tike Over a year ago

I think it's not the declaration of i, but the fact, that I declared tables as char and not char *

Collectives™ on Stack Overflow

put pointer values in a array

3 Answers 3

Comments

Comments

5 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

Comments

Comments

5 Comments

Your Answer

Sign up or log in

Post as a guest

Related