create an array of char arrays

Question

If I have 5 arrays of char like this

char a[6] = "";
char b[6] = "";
char c[6] = "";
char d[6] = "";
char e[6] = "";

and I also have this part of code which gets some tokens with strtok and put them in a,b,c,d,e

while(fgets(buff, sizeof(buff), fp) != NULL)
 {
    fputs(buff,stdout);
    FILE *ft = fopen("/home/pi/Desktop/data.txt","a+");
    struct tm *tp;
    time_t t;
    char s[80];
    t = time(NULL);
    tp = localtime(&t);
    strftime(s, 80, "%d/%m/%Y  %H:%M:%S", tp);
    char *pos = strchr(buff,'N');
    if (pos)
    {
         ptr = strtok(buff, "Nodo_,=:V()");
         i = 0;
       while (ptr != NULL)
         {
          if (i == 0)
             strcat(a, ptr); 
          if (i == 2)
             strcat(b, ptr); 
          if (i == 4)
             strcat(c, ptr); 
          if (i == 6)
             strcat(d, ptr); 
          if (i == 8)
             strcat(e, ptr); 
          ptr = strtok(NULL, "Nodo_,=:V()");
          i++;
         }
      printf("Results: %s, %s, %s, %s, %s\n", a, b, c, d, e);

my question is how can I create a new array (example TABLE) with these 5 values like

a
b
c
d
e

and secondly is there any way to convert this array to

a b c d e

I do not understand the question either? Is it about memory layout? Or about how are the values printed to the screen? — Vorac
– Vorac, Commented Jun 19, 2013 at 7:36
Ok I want to save these values a,b,c,d,e in an array vertically. The other question is for my education how to convert an array lets say 5x1 to 1x5. — dali1985
– dali1985, Commented Jun 19, 2013 at 7:47
The language does not allow such a conversion of the dimensions as you want, but most compilers will not complain when you cast the pointer value to the pointer type you want it to be. — jxh
– jxh, Commented Jun 19, 2013 at 8:01

jxh · Accepted Answer · 2013-06-19 07:37:32Z

1

It is not clear what you want, but here's a shot:

char (*TABLE_5x1[5][1])[6] = {
    { &a },
    { &b },
    { &c },
    { &d },
    { &e }
};

char (*TABLE_1x5[1][5])[6] = {
    { &a, &b, &c, &d, &e }
};

answered Jun 19, 2013 at 7:37

jxh

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4 Comments

dali1985 Over a year ago

If I have also &f &j I will do it like this char (*TABLE_1x5[1][7])[8]= {{ &a, &b, &c, &d, &e, &f, &j }};

jxh Over a year ago

@dali1985: As long as each of them are char[8], and you should probably also rename the variable name to match the new size.

dali1985 Over a year ago

Thank you for your answer. One last question, in your way, if I want the &e to change it with 0 how can I declare it?Like this '0'?

jxh Over a year ago

If I understand you correctly, you would do TABLE_1x5[0][4] = 0;

Dayal rai · Accepted Answer · 2013-06-19 07:35:49Z

0

define char* TABLE[5]. and then you can put a,b,c...into this array as its elements.

answered Jun 19, 2013 at 7:35

Dayal rai

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