How to look for a string inside an array of objects(structure)

Question

Here is a small example:

var distinctValues = [];
distinctValues.push("Value1");
distinctValues.push("Value2");

var firstValue = distinctValues[0];

var searchResults = [];

var data = grid.jqGrid('getGridParam', 'data');
data.forEach(function (row) {

  searchResults[searchResults.length] =
  {
    "ID"       : row.ID,
    "CreatedBy": row.CreatedBy,
    "UpdatedBy": row.UpdatedBy
  }
}

How do I look firstValue("Value1") inside searchResults array and retrieve the CreatedBy information?

//something like this - this is wrong syntax by the way
if ($.inArray(firstValue, searchResults) != -1) {
      alert(searchResults["CreatedBy"]);
}

PSL · Accepted Answer · 2013-06-13 19:53:09Z

1

I think you may want to do this:

var searchResults = [];
data.forEach(function (row) {

  searchResults.push({ //Push to push the record to the array
    "ID"       : row.ID,
    "CreatedBy": row.CreatedBy,
    "UpdatedBy": row.UpdatedBy
  });
}

You can use jquery $.inArray or Array.prototype.indexOf

searchResults is an array of objects so use indexer i.e searchResults[index]["CreatedBy"] instead of searchResults["CreatedBy"]:

var idx = searchResults.indexOf(firstValue); //or var idx = $.inArray(firstValue, searchResults)
if (idx  > -1) {
      alert(searchResults[idx]["CreatedBy"]);  //item Found
}

Nothing wrong with your syntax for $.inArray, Provided you have jquery included in your code.

Since your match is against an object property you can try this:

   var result = $.grep(searchResults, function(value)
   {
       return value.ID === firstValue;
   });

  console.log(result[0].CreatedBy); //result will be an array of matches.

edited Jun 13, 2013 at 19:53

answered Jun 13, 2013 at 5:18

PSL

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10 Comments

rab Over a year ago

we can use arr[arr.length] for adding elements .. but arr.push is more fastest

Max Over a year ago

Unfortunately that always returns -1. I debugged it and can see that the value exists in the array :-(

PSL Over a year ago

@Max How does your array look and value? Definitely has to be some issue with the data only... can you a console.log of your array and the data you are trying to compare. We will try it in a fiddle.

Max Over a year ago

I also tried: var arr = $.grep(searchJobInfoResults, function (n, i) { return (n == value); });

Max Over a year ago

Here is it: TraceInfo("Value: " + value); TraceInfo("1st element: " + searchJobInfoResults[0]["GroupInstanceID"]); TraceInfo("1st element: " + searchJobInfoResults[0]["CreatedBy"]); Value: e6cc8074-d51f-4038-bc97-a3bd22e53bc7 1st element: e6cc8074-d51f-4038-bc97-a3bd22e53bc7 1st element: DOMAIN01\JOHNB

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