Javascript splitting string using only last splitting parameter

Question

An example of what im trying to get:

String1 - 'string.co.uk' - would return 'string' and 'co.uk'
String2 - 'random.words.string.co.uk' - would return 'string` and 'co.uk'

I currently have this:

var split= [];
var tld_part = domain_name.split(".");
var sld_parts = domain_name.split(".")[0];
tld_part = tld_part.slice(1, tld_part.length);
split.push(sld_parts);
split.push(tld_part.join("."));

With my current code, it takes the split parameter from the beginning, i want to reverse it if possible. With my current code it does this:

String1 - 'string.co.uk' - returns 'string' and 'co.uk'
String2 - 'random.words.string.co.uk' - would return 'random` and 'words.string.co.uk'

Any suggestions?

You could just slice negative like string.split('.').slice(-3), then build the string. — elclanrs
– elclanrs, Commented Jun 10, 2013 at 8:03

Owen Allen · Accepted Answer · 2013-06-10 08:21:33Z

2

To expand upon elclanrs comment:

function getParts(str) {
    var temp = str.split('.').slice(-3) // grabs the last 3 elements
    return {
        tld_parts : [temp[1],temp[2]].join("."),
        sld_parts : temp[0]
    }
}

getParts("foo.bar.baz.co.uk") would return { tld_parts : "co.uk", sld_parts : "baz" }

and

getParts("i.got.99.terms.but.a.bit.aint.one.co.uk") would return { tld_parts : "co.uk", sld_parts : "one" }

edited Jun 10, 2013 at 8:21

answered Jun 10, 2013 at 8:12

Owen Allen

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1 Comment

Edgar Over a year ago

What if theres more random words in the string, like lets say more.random.words.in.string.co.uk, then the -3 wouldnt work right?

sangram parmar · Accepted Answer · 2013-06-10 08:23:16Z

0

try this

var str='string.co.uk'//or 'random.words.string.co.uk'
var part = str.split('.');
var result = part[part.length - 1].toString() + '.' + part[part.length - 1].toString();
alert(result);

answered Jun 10, 2013 at 8:23

sangram parmar

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Comments

U.P · Accepted Answer · 2013-06-10 08:27:51Z

0

One way that comes to mind is the following

var tld_part = domain_name.split(".");
var name = tld_part[tld_part.length - 2];
var tld = tld_part[tld_part.length - 1] +"."+ tld_part[tld_part.length];

edited Jun 10, 2013 at 8:27

answered Jun 10, 2013 at 8:14

U.P

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Comments

Pebbl · Accepted Answer · 2013-06-10 10:19:54Z

Depending on your use case, peforming direct splits might not be a good idea — for example, how would the above code handle .com or even just localhost? In this respect I would go down the RegExp route:

function stripSubdomains( str ){
  var regs; return (regs = /([^.]+)(\.co)?(\.[^.]+)$/i.exec( str ))
    ? regs[1] + (regs[2]||'') + regs[3]
    : str
  ;
};

Before the Regular Expression Police ~~attack~~ reprimand me for not being specific enough, a disclaimer:

The above can be tightened as a check against domain names by rather than checking for ^., to check for the specific characters allowed in a domain at that point. However, my own personal perspective on matters like these is to be more open at the point of capture, and be tougher from a filtering point at a later date... This allows you to keep an eye on what people might be trying, because you can never be 100% certain your validation isn't blocking valid requests — unless you have an army of user testers at your disposal. At the end of the day, it all depends on where this code is being used, so the above is an illustrated example only.

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