I think the question title seems to explain eveything. I want to detect whether a string is in URL format or not using javascript.
Any help appreciated.
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8 Answers
Try this-
function isUrl(s) {
var regexp = /(ftp|http|https):\/\/(\w+:{0,1}\w*@)?(\S+)(:[0-9]+)?(\/|\/([\w#!:.?+=&%@!\-\/]))?/
return regexp.test(s);
}
usage: if (isUrl("http://www.page.com")) alert("is correct") else alert("not correct");
2 Comments
Nishant Kelkar
Hi @MarkRedman, the resource on snippets.dzone that you have linked to seems to have been moved ( I get a 410 Gone error message). Is there an updated version of it? Thanks!
Joyce
Take note that
s must be in lowercase.function IsURL(url) {
var strRegex = "^((https|http|ftp|rtsp|mms)?://)"
+ "?(([0-9a-z_!~*'().&=+$%-]+: )?[0-9a-z_!~*'().&=+$%-]+@)?" //ftp的user@
+ "(([0-9]{1,3}\.){3}[0-9]{1,3}" // IP形式的URL- 199.194.52.184
+ "|" // 允许IP和DOMAIN（域名）
+ "([0-9a-z_!~*'()-]+\.)*" // 域名- www.
+ "([0-9a-z][0-9a-z-]{0,61})?[0-9a-z]\." // 二级域名
+ "[a-z]{2,6})" // first level domain- .com or .museum
+ "(:[0-9]{1,4})?" // 端口- :80
+ "((/?)|" // a slash isn't required if there is no file name
+ "(/[0-9a-z_!~*'().;?:@&=+$,%#-]+)+/?)$";
var re=new RegExp(strRegex);
return re.test(url);
}
Debuggex Demo (Improved version which matches also 'localhost')
6 Comments
Anoyz
This was the best one I found so far. The only thing, it returns true to isURL("http").
algorhythm
very nice. 'https|http|ftp...' can written shorter => 'https?|ftp...'
algorhythm
Improved version to match even 'localhost': add '|localhost' after
+ "[a-z]{2,6})" // first level domain- .com or .museum inside the bracket => + "[a-z]{2,6}|localhost)" // first level domain- .com or .museum
egurb
IsURL('11/01/2020') --> true
ramashish tomar
it is not accurate any string let say console.log(IsURL("rama")); it returns true.
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try something like this:
function isUrl(s) {
var regexp = /(ftp|http|https):\/\/(\w+:{0,1}\w*@)?(\S+)(:[0-9]+)? (\/|\/([\w#!:.?+=&%@!\-\/]))?/
return regexp.test(s);
}
answered Nov 9, 2009 at 15:50
Anthony Forloney
92.1k14 gold badges119 silver badges116 bronze badges
1 Comment
Vinee
isUrl() function does not work for "localhost/myprojects", "127.0.0.1/myprojects"
One for the future using the URL constructor and a basic try catch statement, it is supported in most modern browsers. Obviously no IE support...
const isUrl = (str) => {
try {
new URL(str);
return true;
} catch () {
return false;
}
}
If the URL is valid it will get parsed by the constructor and return true.
If the string is not a valid URL the constructor will chuck a syntax error that will get caught and return false.
1 Comment
tdc
Note that this will technically pass as valid with the URL constructor:
http://www.Try this code. This expression is more complete and takes into account IP address:
function checkUrl(s) {
var regexp = /^(?:http(s)?:\/\/)?[\w.-]+(?:\.[\w\.-]+)+[\w\-\._~:/?#[\]@!\$&'\(\)\*\+,;=.]+$/
return regexp.test(s); }
Comments
You can use a regular expression for checking the string
^s?https?:\/\/[-_.!~*'()a-zA-Z0-9;\/?:\@&=+\$,%#]+$
Comments
Had the same task, but all of regex that I found online to check validity of a URL were failed in some test cases.
Here is the regex that worked everything:
/^(http:\/\/www\.|https:\/\/www\.|www\.)?[a-z0-9]+([\-\.]{1}[a-z0-9]+)*\.[a-z]{2,5}(:[0-9]{1,5})?(\/.*)?/
However, If the URL was like: google.com It accepted it as valid (which in my specific case, was considered as invalid)
It worked the best I had found. Worked like a charm!
Comments
When given the option, I prefer the simplest solution.
Use _.startsWith(string, 'http') if:
- You don't mind if URL is invalid
- You're sure the URL being checked will always start with 'http'
- You don't expect the string to be another value that might start also with 'http'
