I looked for an good answer but found none.
An API returns JSON like this [{id:31, name:"blue"},{id:22, name:"green"},..]
I would like to like to get the name from id $api->[where id= 2]
The only way I found was to convert this array to obj and having the id as key. Is there no better PHP way?
Your solution is the best way. Something like:
$results = json_decode($returned_JSON_string);
foreach($results as $result) {
if($result->id == 2) {
// Match!
break;
}
}
If you don't like the default behavior of json_decode creating an object, you can instruct it to create an array like this:
$results = json_decode($returned_JSON_string, true);
$Obj = new stdClass(); foreach ($jobs as $item) { $key = 'id'.$item['id']; $Obj->$key = $item; } print_r($Obj->id12);
12 existed, but I'd go with the safer approach and loop through as I suggested. That way, you can just execute whatever you need to do with a particular ID (2, in my example, 12 in yours) where I commented // Match!.I think you can just encode your json as associative array
$arr = json_decode($json, true); //note true as second parameter because we want as associative array
and now you can call it with
echo $arr[1]['id'];
or loop in the array.
You could use array_filter:
$results = json_decode($returned_JSON_string);
$item = array_filter ($results, function($item) { $item['id'] == 2; });
Here is the solution for doing it in javascript
function myIndexOf(arr, o) {
for (var i = 0; i < arr.length; i++) {
if (arr[i].id == o) {
return i;
}
}
return -1;
}
var data = [{id:1, name:"blue"},{id:2, name:"green"}];
alert(data[myIndexOf(data,2)].name);
PHP version
function myIndexOf($arr, o) {
for (var i = 0; i < count(arr); i++) {
if ($arr[i]['id'] == o) {
return i;
}
}
return -1;
}
$data = json_decode($json_data);
echo $data[myIndexOf($data, 2)]['name']; // will output 'green'
id:2always be the 2nd position? If so you could doecho $json[1]['name']