Sort array using another array in Javascript in IE8 [duplicate]

Question

I have got an array like this:

[1, Stopped]
[2, Waiting]
[3, Finished]
[4, Stopped]
[5, Running]

The number is the id of the program and the text is the status of the program. I need to sort this array according to the next order:

['Error','Halted','Blocked','Finished','Waiting to Start','Waiting','Stopping','Running','Idle','Stopped','Opened','Ready'];

I use this for every other browser except IE8:

var a = [[1, 'Stopped'],
[2, 'Waiting'],
[3, 'Finished'],
[4, 'Stopped'],
[5, 'Running']];
var order = ['Error','Halted','Blocked','Finished','Waiting to Start','Waiting','Stopping','Running','Idle','Stopped','Opened','Ready'];

a.sort(function (a, b) {
   return order.indexOf(a[1]) - order.indexOf(b[1]);
});

It is working in all different browsers except for IE8. Can anyone tell me how to sort it in IE8?

Have a look here - stackoverflow.com/questions/1744310/…. Have you implemented a workaround for the indexOf functionality? array.indexOf() is not supported in IE8 — Mark Walters
– Mark Walters, Commented May 30, 2013 at 8:18
In particular, you need to use what is called a "polyfill" to patch in the missing functionality. Here is one you can copy/paste: developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… — Jon
– Jon, Commented May 30, 2013 at 8:22
I looked at tha, but I have no idea how to implement that into my code. Every time I try to implement it, all browsers stop working. — Extigo
– Extigo, Commented May 30, 2013 at 8:23
@user1350637: Then you are making some type of elementary syntax error. Look at the console of a developer-friendly browser for error messages. — Jon
– Jon, Commented May 30, 2013 at 8:23

Spudley · Accepted Answer · 2013-05-30 12:48:24Z

2

IE8 does not support array.indexOf(). You'll need to find an alternative.

Possible solutions:

Use jQuery (or a similar library), which gives $.inArray() as a direct replacement for array.indexOf().
Use a polyfill library that adds a replacement .indexOf method to the Array prototype. Here's one possible option. (others available via google of course)
Rewrite your code to search through the array using a simple loop.

edited May 30, 2013 at 12:48

answered May 30, 2013 at 8:32

Spudley

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