How can I change a list of strings into CSV in Python?

Question

Example strings:

uji708
uhodih
utus29
agamu4
azi340
ekon62

I need to change them into CSV list like this:

uji708,uhodih,utus29,  
agamu4,azi340,ekon62,

My code so far:

email = 'mail_list.txt'
handle = open(email)

for line in handle:
    try:
        email = line.split()[0].replace('\n', '')
        l = line.split()
        print '\n'.join((','.join(x) for x in zip(l[::3], l[1::3], l[2::3])))    
    except:
        print 'error'

How can I do this in Python?

thanks reply, actually im handling email list. can i use such like follow style? maillist = 'scrap_daum.txt' try: handle = open(maillist) except: exit(1) for line in handle: #currline += 1 valid = [] try: email = line.split(':')[0].replace('\n', '') except: exit(1) — paul
– paul, Commented Nov 4, 2009 at 7:19
hello i was update pastebin site i want to handle email list — paul
– paul, Commented Nov 4, 2009 at 7:33

Robert Rossney · Accepted Answer · 2009-11-05 15:40:04Z

2

Use csv.writer:

import csv
import sys

writer = csv.csvwriter(sys.stdout)
writer.writerow(iterable_containing_my_strings)

answered Nov 5, 2009 at 15:40

Robert Rossney

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1 Comment

jfs Over a year ago

iterable_containing_my_strings = open('mail_list.txt')

score 0 · Accepted Answer · 2009-11-04 06:24:28Z

0

Here is a very specific answer to a very specific question when you will clarify/generalize your question I may update my answer

s = """
uji708
uhodih
utus29
agamu4
azi340
ekon62
"""
l = s.split()
print '\n'.join((','.join(x) for x in zip(l[::3], l[1::3], l[2::3])))

answered Nov 4, 2009 at 6:24

1 Comment

paul Over a year ago

hello thanks for your reply.. can i use some other method? i was updated pastebin :) elca.pastebin.com/d4556c585

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