Array of arraylists

Question

im having trouble making an array of arraylists, heres's the code :
'ArrayList<Integer>[] solucao= new ArrayList[6];' and using this code below:

           solucao[0].add(1);
            solucao[0].size();
                solucao[1].size();
                solucao[1].add(1);
            solucao[2].size();
            solucao[2].add(1);
                solucao[3].size();
                solucao[3].add(1);
            solucao[4].size();
            solucao[4].add(1);
                solucao[5].size();
                solucao[5].add(1);
            solucao[6].size();
            solucao[6].add(1);
                solucao[7].size();
                solucao[7].add(1);

all the calls for size return null. Anyone knows how to solve it?

Im looking for a data structure of array of arraylists, as each array[i] position will return me an arraylist of integers.

thank you

you can check here stackoverflow.com/questions/10227201/… to be precise ArrayList<Integer>[] solucao = (ArrayList<Integer>[])new ArrayList[10]; — GustyWind
– GustyWind, Commented May 22, 2013 at 5:05

Zong · Accepted Answer · 2013-05-22 05:22:05Z

3

You have to initialize each ArrayList in the array.

ArrayList[] solucao = new ArrayList[6];
for (int i = 0; i < solucao.length; i++)
    solucao[i] = new ArrayList();

I actually thought you couldn't have an array of ArrayList. Apparently you can, but it must be non-generic. You should probably reconsider why you're doing this...

edited May 22, 2013 at 5:22

answered May 22, 2013 at 5:06

Zong

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Aniket Thakur · Accepted Answer · 2013-05-22 05:10:05Z

0

Arrays are just pointers or references. For each for them you have to create a new ArrayList object and store your data in it.

List[] solucao= new ArrayList[5];
for(int i=0;i<solucao.length;i++)
{
  solucao[i]  = new ArrayList();
  solucao[i].add(yourObject);
}

answered May 22, 2013 at 5:10

Aniket Thakur

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djechlin · Accepted Answer · 2013-05-22 05:37:14Z

0

ArrayList<Integer>[] solucao= new ArrayList[6];

Should be new ArrayList<Integer>[6]

Note an IDE would give you a warning about this. Next, initialize each element of the array (Java 7):

for(int i = 0; i < solucao.length; i++) {
    solucao[i] = new ArrayList<>();

edited May 22, 2013 at 5:37

answered May 22, 2013 at 5:06

djechlin

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2 Comments

Zong Over a year ago

It actually specifically shouldn't be new ArrayList<Integer>[6] in this case. Also, the for each loop doesn't work for assignments.

djechlin Over a year ago

@ZongLi re. second yes you're right, bad mistake on my part. re. first, really? I should learn how templates + arrays work I guess.

kartavya soni · Accepted Answer · 2013-05-22 06:09:48Z

0

For store data first you have to create object.

ArrayList<Integer>[]  ls =  new ArrayList[7];
for (int i = 0; i < ls.length; i++) {
    ls[i] =  new ArrayList<Integer>();
    for(int j = 0 ; j<i ;j++){
        ls[i].add(j);   
    }
    System.out.println(ls[i].size());
}

answered May 22, 2013 at 6:09

kartavya soni

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