Im trying to get all the power calculations out of a string using reg exp's i tried the following code:
var regex = new RegExp('[0-9]+[^]{1}[0-9]+');
regex.exec('1^2');
this works and returns 1^2 but when i try to use the following string:
regex.exec('1+1^2');
it returns 1+1
This is because [^xyz] means "not x, y, or z." ^ is the "not" operator in character classes ([...]). To fix this, simply escape it (one backslash to escape the ^, and another to escape the first backslash since it's in a string and it's a special character):
var regex = new RegExp('[0-9]+[\\^]{1}[0-9]+');
Also, you don't need to use character classes and the {1} if you only have one character; just do this:
var regex = new RegExp('[0-9]+\\^[0-9]+');
Finally, one more improvement - you can use literal regular expression syntax (/.../) so you don't need two backslashes:
var regex = /[0-9]+\^[0-9]+/;
[0-9]+\^[0-9]+ won't work - it needs 2 escape slashes: [0-9]+\\^[0-9]+
/.../). Updated answer.
^ negates the character class only when it is at the start of the character class. It loses its meaning elsewhere[^] in regex terms is a character class ([]) that's been inverted (^). e.g. [^abc] is "any character that is NOT a, b, or c". You need to escape the carat: [\^].
As well, {1} is redundant. Any character class or individual character in a regex has an implied {1} on it, so /a{1}b{1}c{1}/ is just a very verbose way of saying /abc/.
As well, a single-char character class is also redundant. /[a]/ is exactly the same as /a/.
^is not operator. Try[0-9]+[\^]{1}[0-9]+[/^]^issue.[\].