how to parse a JSON string which is inside a array

Question

I have a json of following format:

{
    "Result": {
        "question": "Barack Obama vs Mitt Romney?",
        "option": [
            "Barack Obama",
            "Mitt Romney",
            "Other"
                   ],
        "percentage": [
            20,
            40,
            80
                      ]
               }
}

and I am using following code to parse it but this giving null pointer exception at option array.

JSONParser jParser = new JSONParser();

                    JSONObject json = jParser.getJSONObjectFromUrl(url);
                    Log.e("json",json.toString());

                    Log.e("-------url-------", ""+url);


                        String resultStr = json.getString("Result"); 
                        Log.e("result string ",resultStr);

                        JSONObject jsonObject2 = new JSONObject(resultStr);


                        String question_string = jsonObject2.getString("question"); 
                        Log.e("question String ",question_string);


                        String option_str = jsonObject2.getString("option"); 

                        JSONArray optionArray = new JSONArray(option_str);
                        Log.d("option array", String.valueOf(optionArray.length()));

Here is your homework: Android - JSON Parsing example

Paresh Mayani
– Paresh Mayani

2013-05-13 06:56:53 +00:00
Commented May 13, 2013 at 6:56 — Paresh Mayani
– Paresh Mayani, Commented May 13, 2013 at 6:56

Nermeen · Accepted Answer · 2013-05-13 06:49:21Z

1

You need to get the json array this way:

JSONArray optionArray = jsonObject2.getJSONArray("option");
Log.d("option array", String.valueOf(optionArray.length()));

check http://www.androidhive.info/2012/01/android-json-parsing-tutorial/

answered May 13, 2013 at 6:49

Nermeen

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Comments

BobTheBuilder · Accepted Answer · 2013-05-13 06:50:38Z

0

Use:

JSONArray optionArray = jsonObject2.getJSONArray("option");

as "option" key points to an array and not to a String.

edited May 13, 2013 at 6:50

answered May 13, 2013 at 6:49

BobTheBuilder

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Comments

Gabe Sechan · Accepted Answer · 2013-05-13 06:51:07Z

0

You're going way too complicated here, and not using those lovely GetJSONObject and getJSONArray functions, which will cause you to double parse a lot. Try this

                JSONParser jParser = new JSONParser();

                JSONObject json = jParser.getJSONObjectFromUrl(url);
                Log.e("json",json.toString());

                Log.e("-------url-------", ""+url);

                    JSONObject jsonObject2 = json.getJSONObject("Result");


                    String question_string = jsonObject2.getString("question"); 
                    Log.e("question String ",question_string);

                    JSONArray optionArray = jsonObject2.getJSONArray("option");

answered May 13, 2013 at 6:51

Gabe Sechan

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2 Comments

Supericy Over a year ago

new JSONObject("Result") you sure about that?

Gabe Sechan Over a year ago

Nope. That's what I get from copy and pasting his code and editing rather than writing from scratch. Thanks for the catch.

newBie · Accepted Answer · 2013-05-13 07:00:39Z

0

Instead of using

 String option_str = jsonObject2.getString("option");

use this :

 JSONARRAY optionArray = jsonObject2.getJSONAray("option");
 for(int i=0;i<optionArray.length; i++){
    String option = optionArray[i].getString();}

Try this..

answered May 13, 2013 at 7:00

newBie

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