C# problem with byte[]

Question

I am loading a file into a byte[]. By my understanding the byte[] should contain a specific elements of bytes (8-bit). When i print each byte, all of them are not 8-bit (i.e. they dont have the length of 8). My Code:

FileStream stream = File.OpenRead(@"C:\Image\Img.jpg");
byte[] fileByte = new byte[stream.Length];
stream.Read(fileByte, 0, fileByte.Length);

for (int i = 0; i <= fileByte.Length - 1; i++)
{
  Console.WriteLine(Convert.ToString(fileByte[i], 2));
}

Output:

I think my understanding is wrong here, Can you please let me know (or provide me some tutorial links) where I am missing this.

byte[] data = File.ReadAllBytes(@"FilePath.jpg");

Sam Harwell
– Sam Harwell

2009-10-29 15:53:57 +00:00
Commented Oct 29, 2009 at 15:53 — Sam Harwell
– Sam Harwell, Commented Oct 29, 2009 at 15:53

Michael Myers · Accepted Answer · 2009-10-29 15:40:46Z

18

Leading 0's don't get printed.

answered Oct 29, 2009 at 15:40

Michael Myers♦

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6 Comments

mjv Over a year ago

Amazing, all the "love" you're getting from this simple response... (no jealousy on my part, you beat us all time wise, plus I'm 200 for the day), but isn't it funny when we get so many reps for these simple questions?

David Over a year ago

@mvj - No kidding! But I AM jealous. But big enough to deal with it. (grin).

Jonathan Fingland Over a year ago

@mjv my highest rep answers have usually been the easiest to answer. Questions involving specialized knowledge, lots of references, etc rarely get more than a few up votes just because so few actually know if the answer is correct or not. Probably the same for mmyers and I'm sure he's happy to take the rep even if it's for an easy one.

Michael Myers Over a year ago

Yeah, especially considering that my entire knowledge of C# consists of things I've read on SO. :)

David Over a year ago

Yeah... And he was the quickest to answer. Good for him!

|

David · Accepted Answer · 2009-10-29 15:51:31Z

13

When converting a numeric to a string, you lose any leading zeros. (Note that all of your entries start with "1".) You can use PadLeft to put them back in.

   FileStream stream = File.OpenRead(@"C:\Image\Img.jpg"); 
   byte[] fileByte = new byte[stream.Length]; 
   stream.Read(fileByte, 0, fileByte.Length); 

   for (int i = 0; i <= fileByte.Length - 1; i++) 
   { 
      Console.WriteLine(Convert.ToString(fileByte[i], 2).PadLeft(8,'0')); 

   }

edited Oct 29, 2009 at 15:51

answered Oct 29, 2009 at 15:45

David

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4 Comments

Michael Myers Over a year ago

Thanks, this is the part that I was missing. (I have only a vague knowledge of C#.)

Kevin Over a year ago

Instead of PadLeft(8,Convert.ToChar("0")), just do PadLeft(8,'0'). No sense converting the string to a char every single time.

David Over a year ago

Man,you all beat me to the answer because I toook the time to write and test the "fix" code." Still, + to everyone who answered correctly.

David Over a year ago

@Kevin, Thank you. I don't work with the char data type a lot, so I didn't realize the single quotes made teh difference. Changing my answer to match.!

Nestor · Accepted Answer · 2009-10-29 15:42:21Z

4

They all have 8 bits, but the non significant zeroes (the zeroes on the left) are not printed.

answered Oct 29, 2009 at 15:42

Nestor

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Comments

mjv · Accepted Answer · 2009-10-29 15:41:58Z

3

It is simply that the leading zeros are not included...

answered Oct 29, 2009 at 15:41

mjv

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Comments

Gabriel Magana · Accepted Answer · 2009-10-29 15:42:01Z

2

Are the bytes without leading zeros? You kinda chose a bad example because we do not know the decimal values you are displaying (ok maybe someone who knows the header structure for a .jpg file knows). I'm willing to bet leading zeros are not displayed in the binary equivalents.

answered Oct 29, 2009 at 15:42

Gabriel Magana

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