JavaScript embedded function within function

Question

I came across this example on the MDN and it doesn't work as described:

function makePerson(first, last) {
    return {
        first: first,
        last: last,
        fullName: function() {
            return this.first + ' ' + this.last;
        },
        fullNameReversed: function() {
            return this.last + ', ' + this.first;
        }
    }
}

Example Call:
> s = makePerson("Simon", "Willison")
> s.fullName()
Simon Willison
> s.fullNameReversed()
Willison, Simon

The article was written in 2006, and in both IE10 and Chrome 26, it just displays the literal code for the fullName and fullNameReversed functions. Is this functionality no longer working for modern browsers?

That code does work. Maybe you forgot the calling parentheses when you tried it? — bfavaretto
– bfavaretto, Commented May 7, 2013 at 22:58
Yes, it appears I forgot the calling parentheses. Thanks everyone. — Josh
– Josh, Commented May 8, 2013 at 14:26

Nick · Accepted Answer · 2013-05-07 23:10:17Z

1

It sounds like you've missed out the parentheses from the end of your function call.

Try

s.fullName();

instead of

s.fullName;

answered May 7, 2013 at 23:10

Nick

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Comments

Xotic750 · Accepted Answer · 2013-05-07 23:01:33Z

1

Appears to work just fine on chromium v25

Javascript

function makePerson(first, last) {
    return {
        first: first,
        last: last,
        fullName: function() {
            return this.first + ' ' + this.last;
        },
        fullNameReversed: function() {
            return this.last + ', ' + this.first;
        }
    }
}

var s = makePerson("Simon", "Willison");
console.log(s.fullName());
console.log(s.fullNameReversed());

Output

Simon Willison
Willison, Simon

On jsfiddle

answered May 7, 2013 at 23:01

Xotic750

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Comments

Pooyan Arab · Accepted Answer · 2013-05-07 23:06:19Z

1

If you receive the code for the function, it is probably because you call the function like s.fullName and not s.fullName() (You are missing the parenthesis)

answered May 7, 2013 at 23:06

Pooyan Arab

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