Python 3: how to compare multiple strings in one line of code? [duplicate]

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Why does "a == x or y or z" always evaluate to True? How can I compare "a" to all of those? (8 answers)

Why does non-equality check of one variable against many values always return true? (3 answers)

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I'm trying to make a category select (by text interface) in Python 3, and I was wondering how I can compare if multiple strings are not true, and then print something along the lines of "that is not a valid choice"

    input("what is your category choice?")
    if categoryChoice != "category1", "category 2", "category 3":
    print("not a valid choice")

I don't understand the syntax for having it check if any of category1, category2, category3, etc is true/false

Matt Ball · Accepted Answer · 2013-05-06 04:38:34Z

8

Use in for containment tests.

categoryChoice = input("what is your category choice?")
if categoryChoice not in ("category1", "category 2", "category 3"):
    print("not a valid choice")

http://ideone.com/e6n0Rr

By the way, if you're using Python 2, you should really use raw_input instead of input.

edited May 6, 2013 at 4:38

answered May 6, 2013 at 3:48

Matt Ball

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