Avoiding eval(), I need a way to pass multiple arguments to a variable function

Question

Trying to pass multiple parameters to a variable function call..

function myFunction(myvar,time){
    alert(myvar);   
}

t_function = "myFunction";
t_params = "haha,hehe";
window[t_function](t_params);

I basically need to mimic this call

myFunction("haha","hehe");

I can't set a specific amount of params in the variable function call, like

// I will not know how many params a function will need.
window[t_function](t_params1,t_params2,etc);

Any ideas? I'm tempted to use eval.

------ ended up doing this -----

function myFunction(myvar1,myvar2){ alert(myvar1 + " and " + myvar2);

}

t_function = "myFunction";
t_params = [];
t_params[0] = "haha";
t_params[1] = "hehe";

window[t_function].apply(this,t_params);

thanks all, specially to Joseph the Dreamer

You can actually declare the array as var t_params = ['hello','world']; — Joseph
– Joseph, Commented Apr 26, 2013 at 3:29

Joseph · Accepted Answer · 2013-04-26 03:28:14Z

2

You need apply, which takes in a value for this in your function, and an array of arguments:

window[t_function].apply(this,[arg1,arg2,...,argN]);

And the function will receive it as:

function myFunction(arg1,arg2,...,argN){...}

Every value passed into the invoked function can be accessed via the array-like arguments. This is useful especially when the arguments are dynamic. Thus, you can do something like:

function myFunction(){
  var arg1 = arguments[0]; //hello
  var arg2 = arguments[1]; //world
}

//different ways of invoking a function
myFunction('hello','world');
myFunction.call(this,'hello','world');
myFunction.call(this,['hello','world']);

edited Apr 26, 2013 at 3:28

answered Apr 26, 2013 at 3:16

Joseph

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2 Comments

BrownChiLD Over a year ago

will that pass an array into my function? or arguments as if they were called directly myFunction(arg1,arg2) . because if that passes an array into the function then i have to mod my function to process array as parameters/arguments

Joseph Over a year ago

@BrownChiLD updated the answer, and read the documentation for apply

Niet the Dark Absol · Accepted Answer · 2013-04-26 03:16:35Z

1

If you can reliably use , as a separator, try this:

window[t_function].apply(null,t_params.split(","));

answered Apr 26, 2013 at 3:16

Niet the Dark Absol

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2 Comments

Musa Over a year ago

I think t_params is a string of variable names not values.

Niet the Dark Absol Over a year ago

"i basically need to mimic this call myFunction("haha","hehe");" Strings, not variables ;)

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