How to accept multiple input into a same script

Question

How can I accept multiple-line input into a same script. Or in other words to process multiple files with the following script:

#!/bin/bash
echo 'Enter file names (wild cards OK)'
read input_source
if test -f "$input_source"
then 
sort $var | uniq -c | head -10
fi

choroba · Accepted Answer · 2013-04-19 21:44:43Z

1

Add a for loop:

#!/bin/bash
echo 'Enter file names (wild cards OK)'
read files
for input_source in $files ; do
    if test -f "$input_source" ; then 
        sort $var | uniq -c | head -10  # You probably should include $input_source somewhere
    fi
done

answered Apr 19, 2013 at 21:44

choroba

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1 Comment

Zerg12 Over a year ago

Thanks! And if I want to repeat the sort $input_source | uniq -c | head -10 for the input files over and over until the user indicates end-of-file. This is done by entering the single character Ctrl-d as a file name. Any ideas ??

DVK · Accepted Answer · 2013-04-19 21:42:43Z

1

Use a while loop:

while read input_source 
do
# Do something with $input_source
done

answered Apr 19, 2013 at 21:42

DVK

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Comments

suspectus · Accepted Answer · 2013-04-19 21:46:36Z

1

Just cat all the files that match the input pattern-:

#!/bin/bash
echo 'Enter file names (wild cards OK)'
read input_source
cat $input_source | sort | uniq -c | head -10

answered Apr 19, 2013 at 21:46

suspectus

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