Passing two variables to one JavaScript function

Question

I have completed if I pass a variable id but now I want to pass name to the same function when I click on a image. This is my code:

 for (var i = 0; i <friend_data.length; i++) {
                        results += '<div class = "clicker" id = "'+friend_data[i].id+'" onclick="javascript:testId(this.id,'+ friend_data[i].name+')"><img src="https://graph.facebook.com/' + friend_data[i].id + '/picture" height="30" width="30">' + friend_data[i].name + '</div>';
                    }

and

function testId(id, friend_data[id].name ){
    alert(id);
    alert(friend_data[i].name);     
}

The alert(friend_data[i].name); does not show because it's wrong. Please help me to correct it. Please look in even onclick it's the right ways to pass variable?

No, it's alert only ID value but when I give it's alert name, It's errors — pov
– pov, Commented Apr 19, 2013 at 10:15
friend_data[id].name is not a valid parameter name. (mothereff.in/js-variables) — Anirudh Ramanathan
– Anirudh Ramanathan, Commented Apr 19, 2013 at 10:18
friend_data[id].name is show my friend name is sure if I call in correct ways because I used it to show name of my fecebook's friend again already. — pov
– pov, Commented Apr 19, 2013 at 10:26
please help me to solve it. I know my code is not correct but I want to show it to everybody for see it and help me to modifier it. — pov
– pov, Commented Apr 19, 2013 at 10:32

Samuel Caillerie · Accepted Answer · 2013-04-19 10:15:25Z

4

try this

function testId(id, name ){
    alert(id);
    alert(name);
}

edited Apr 19, 2013 at 10:15

Samuel Caillerie

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answered Apr 19, 2013 at 10:13

muneebShabbir

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Comments

chandresh_cool · Accepted Answer · 2013-04-19 10:14:17Z

3

Change for loop to this

for (var i = 0; i <friend_data.length; i++) {
results += '<div class = "clicker" id = "'+friend_data[i].id+'" onclick="javascript:testId(this.id,'+friend_data[i].name+')"><img src="https://graph.facebook.com/' + friend_data[i].id + '/picture" height="30" width="30">' + friend_data[i].name + '</div>';
}

answered Apr 19, 2013 at 10:14

chandresh_cool

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6 Comments

pov Over a year ago

While I add + to my code but I still get the same result, it's can't get name values

chandresh_cool Over a year ago

Did u change ur function function testId(id, friend_data[id].name ){ to function (id, name) ?

pov Over a year ago

No I am not. It's still function testId(id, friend_data[id].name ){ alert(id); alert(friend_data[i].name); }

chandresh_cool Over a year ago

change it to function testId(id,name) { alert(id); alert(name); }

pov Over a year ago

I don't know why it's nothing is happened. but when I view it in firebug add-on , it's show SyntaxError: missing ) after argument list [Break On This Error] javascript:testId(this.id,Chan Vireak) that when I checked it's not miss ) . other one it's show ìd` value it's stop show. right ?

|

Mariusz Jamro · Accepted Answer · 2013-04-19 10:14:37Z

2

You forgot to add + in the code '+friend_data[i].name+':

for (var i = 0; i <friend_data.length; i++) {
    results += '<div class = "clicker" id = "'+friend_data[i].id+'" onclick="javascript:testId(this.id, '+friend_data[i].name+')"><img src="https://graph.facebook.com/' + friend_data[i].id + '/picture" height="30" width="30">' + friend_data[i].name + '</div>';
}

answered Apr 19, 2013 at 10:14

Mariusz Jamro

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1 Comment

pov Over a year ago

Yes, after I add + to my code but I am still can't get name value to function that I pass too .

phenomnomnominal · Accepted Answer · 2013-04-19 10:14:10Z

0

Your function should be defined as:

function testId(id, name) {
    alert(id);
    alert(name);
}

name will take the value of friend_data[i].name, when the function is called.

answered Apr 19, 2013 at 10:14

phenomnomnominal

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Comments

Toverbal · Accepted Answer · 2013-04-19 10:15:08Z

0

function testId(id, name ){
    alert(id);
    alert(name);
}

And then call it with: testId(friend_data[i].id, friend_data[i].name)

Or

function testId(friend){
    alert(friend.id);
    alert(friend.name);
}

Adnd then call it with: testId(friend_data[i])

answered Apr 19, 2013 at 10:15

Toverbal

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