Java Script is not working inside the php

Question

public function actionAjaxUpdate()
    {   
        $action = $_GET['act'];


        if(!isset($_POST['selectedId']))
        {
            echo '<script> alert("No row is selected"); </script>';
        }

        else
        {
        $selectedAll = $_POST['selectedId'];
        if(count($selectedAll)>0)
        {
            foreach($selectedAll as $selectedId)
            {
                $model=$this->loadCompositeModel($selectedId);
                switch ($action) {
                    case 'Delete':
                        $model['account']->delete();
                        break;
                    case 'Active':
                        $model['account']->active = '1';
                        break;
                    case 'Inactive':
                        $model['account']->active = '0';                     
                        break;
                    default:
                        break;
                }
                $model['account']->save();
            }
        }
        }

    }

List item

In this code Alert is not working, if no id is selected.So some one help me out. i have tried alot but js is not working. I have used js inside the php and this is the first time when js is not working inside the php

please post your form, so we can see what $_POST['selectedId'] is — S.Visser
– S.Visser, Commented Apr 15, 2013 at 7:04
hey condition is correct. i have check it on firebug @ Edwin — user2281489
– user2281489, Commented Apr 15, 2013 at 7:06

Quentin · Accepted Answer · 2013-04-15 07:06:21Z

2

Without seeing the code that makes the HTTP request, it is hard to say what the problem is.

Them most likely explanation that selectedId is set to an empty string when no id has been selected. The condition !isset($_POST['selectedId']) will then not give you the result you want. Use empty() instead (and make sure that 0 is not an acceptable id value).

answered Apr 15, 2013 at 7:06

Quentin

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1 Comment

user2281489 Over a year ago

'columns'=>array( array( 'id'=>'selectedId', 'class'=>'CCheckBoxColumn', //'value'=>'$data->user_status', ), 'uid', 'username', 'password', 'bid', array( 'name'=>'active', //'header'=>'Active', 'filter'=>array('1'=>'Yes','0'=>'No'), 'value'=>'($data->active=="1")?("Yes"):("No")' ), array( 'class'=>'CButtonColumn', ), ), )); ?>

Basic · Accepted Answer · 2013-04-15 07:22:25Z

Unless you're injecting the response back into the page, the Javascript will never be evaluated.

If you were to do...

document.write('<script src="/path/to/phpscript.php">')

then the response will be appended to the page and evaluated.

However, if you do...

$.ajax({
    success: function(response) {
        //Blah....  
    }
});

or something to that effect, the response is never evaluated, it's passed to your success function as a string. So you could just get the PHP to print 1 or 0 for success/failure - or even better return a Json object

<?php

    ...
    if(!isset($_POST['selectedId']))
    {
        $Ret->Success = false;
        $Ret->Reason = "No row is selected";
        header("Content-Type: application/json");
        print json_encode($Ret)
    }     
?>

Then use the $.getJson Ajax call to retrieve the response as a Js object (See this manual page)

Amir · Accepted Answer · 2013-04-15 07:49:48Z

0

It seems $_POST['selectedId'] is an array. then you should use isset for elements of $_POST['selectedId'] for example if (!isset($_POST['selectedId'][0]))

EDIT 1: try this one

$array_id = array_filter($_POST['selectedId']);

then use if (!empty($array_id)) instead of if (!isset($_POST['selectedId']))

edited Apr 15, 2013 at 7:49

answered Apr 15, 2013 at 7:13

Amir

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4 Comments

user2281489 Over a year ago

yes $_POST['selectedId'] is an array. But shall i know element of $_POST['selectedId']

Amir Over a year ago

Then you mean, you don't know elements?

user2281489 Over a year ago

no i mean when i selected a row selectedId returns the id of the row. so how can i use that id

Amir Over a year ago

Where does selectedid come from? put the code or show us what is elements of selectedid? perhaps something like $_POST['selectedId']['id']

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