Php and JSON : object(stdClass) [duplicate]

Question

I have decoded a JSON file into a variable ($tmp). var_dump($tmp) gives:

object(stdClass)#31 (3) {
    ["c"]=> int(2)
    ["r"]=> int(2)
    ["d"]=> object(stdClass)#32 (4) {
                ["1"]=> string(2) "un"
                ["2"]=> string(4) "deux"
                ["3"]=> string(5) "trois"
                ["4"]=> string(6) "quatre"
            }
}

I want to retrieve for example "un" so I do $tmp->d["1"] but it doesn't work. I've got the following error:

Fatal error: Cannot use object of type stdClass as array in File.php on line 17

dm03514 · Accepted Answer · 2013-04-10 13:55:24Z

2

json_decode takes an additional paramater that will turn your json string into an array instead of an object

json_decode($json_str, true)

As comment noted, your d property of your json object is an object not an array, so you can't access it with array notation (as you see there is an error)

I believe

$tmp->d->{'1'}
// "un"

should work in accessing it

edited Apr 10, 2013 at 13:55

answered Apr 10, 2013 at 13:41

dm03514

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2 Comments

Frederik Wordenskjold Over a year ago

This is a workaround. It doesn't answer the question. Why should he turn the string into an array, when it works perfectly fine as an object?

hakre Over a year ago

May I ask you to not answer obvious duplicate questions? Tthose about this error message are already far too many if you take a peek into google results (at least for my taste but I'm sure you won't think much different), instead, why not suggest to close the question as a duplicate? you can also leave some guidance via a comment if you like to be extra helpful to the OP specifically.

Aleksey Stetsenko · Accepted Answer · 2013-04-10 13:48:05Z

0

php has a default function json_encode and json_decode

$arrayOfValues = array();
$jsonString = json_encode($arrayOfValues);

and

$arrayOfValues = json_decode($jsonString);

with this function you can use variabled with json.

answered Apr 10, 2013 at 13:48

Aleksey Stetsenko

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