Say I have a method that needs three arguments:
def foo(a, b, c)
end
And I have said arguments in an array:
[a, b, c]
Is there a trivial or one method way of using the array as the arguments, like:
foo(array.some_method)
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2 Answers
You can use the splat operator:
foo(*array)
4 Comments
steve_gallagher
Does the splat operator have to be in the method's definition? I am trying to use a library class method, so I can't alter the signature of the method.
pjam
No, it's a way of 'exploding' an array to match an existing method signature, so in your example you can use it without altering your
foo methodsteve_gallagher
You're right. Although the code that results its fairly funkified:
Date.valid_date?(*'9666-96-96'.split('-').map(&:to_i)). I probably should make it into two steps.pjam
Looks indeed like an ugly oneliner :)
def foo(*bar)
end
Foo now exacts an array as parameters. You could also make it accept a hash by doing
def foo(bar={})
end
