I am trying this option
#!/bin/ksh
echo $1
awk '{FS="=";print $2}' $1
and on the command line
test_sh INSTANCE=VIJAY
but awk is failing. Is there any problem here?
Basically I need the value VIJAY passed on the command line.
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5 Answers
ksh (and Bash) can do the splitting for you:
#!/bin/ksh
var="${1%=*}"
val="${1#*=}"
echo "Var is $var"
echo "Val is $val"
Running it:
$ ./scriptname INSTANCE=VIJAY
Var is INSTANCE
Val is VIJAY
answered Oct 15, 2009 at 13:14
Dennis Williamson
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for awk, the second parameter is a name of the file to process.
So you asked it to process the file named INSTANCE=VIJAY
Instead, do
echo "$1" | awk '{FS="=";print $2}'
Just to be clear, what this does is pass the input to be processed to awk via standard input through a pipe from output of echo; instead of awk reading it input from a file.
To quote from Awk manual:
If there are no files named on the command line, gawk reads the standard input.
1 Comment
ghostdog74
put the FS variable in BEGIN block.
I think a simpler one is
#!/bin/sh
echo $1
echo $1 | cut -d= -f2
as cut can split on the equal sign as well and then show the second token. Also note that the passing $1 to awk was not correct as that argument is not a file.
answered Oct 15, 2009 at 12:49
Dirk is no longer here
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Comments
I think you left the pipe (|)
echo $1 | awk '{FS="=";print $2}'
Alternative
echo $1 | cut -d'=' -f2
Comments
#!/bin/ksh
echo $1 | cut -f2 -d=
