Multiple arrays loop shell

Question

I have a problem building a "dynamic" array.

First of all I create an array to generate a list of names of files:

declare -a pgidarr=`run "select partition_id from ETL.PARTITION_GROUP_MEMBER where partition_group_id=${PGID}"`
for i in ${pgidarr[@]}
do
ARRLOOP=$i
PAID=`run "select LPAD('${ARRLOOP}',2,'0')"` #LPAD the partition ID
FILENAME=ABCD_${PAID}_000000.txt

Now in the same loop I want to create a NEW array

trigarrat=("${trigarrat[@]}" $FILENAME)

But when I run it doens't replace $FILENAME

On Google I can't find much about arrays and variables, anyone could please help me? ;) Thanks! Alex

bash --version GNU bash, version 3.1.17(1)-release

You could probably use PAID=$(printf "%.2d" $i) to avoid going to the DB just for number formatting. — Jonathan Leffler
– Jonathan Leffler, Commented Mar 27, 2013 at 18:10
You're not initializing pgidarr properly; it's a coincidence that the only element of the array is split into words after you expand the array without quoting it. declare -a pgidarr=( $( run ... ) ), then for i in "${pgidarr[@]}" — chepner
– chepner, Commented Mar 27, 2013 at 18:19

Martijn de Milliano · Accepted Answer · 2013-03-27 18:05:45Z

3

Try using += to append elements to trigarrat:

declare -a pgidarr=`run "select partition_id from ETL.PARTITION_GROUP_MEMBER where partition_group_id=${PGID}"`
trigarrat=()
for i in ${pgidarr[@]}
do
    ARRLOOP=$i
    PAID=`run "select LPAD('${ARRLOOP}',2,'0')"` #LPAD the partition ID 
    FILENAME=ABCD_${PAID}_000000.txt
    trigarrat+=($FILENAME)
done

Reference: http://www.gnu.org/software/bash/manual/bashref.html#Shell-Parameters

answered Mar 27, 2013 at 18:05

Martijn de Milliano

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