Passing a 2D array of strings to a function in c++

Question

I'm trying to pass a 2d and single dimmension array of strings to a function but its not working.

my arrays are:

    string 2Darray[100][100];
    String 1Darray[100];

Now the function:

    void check(string temp2D[100][100], string temp1D[100]);

When I call it:

    check(2Darray,1Darray);

I've tried it other ways ad they all don't work. Thanks in advance for any answers!

string 1Darray ,being a 1D array has two sets of indices , in its declaration ?? — Barath Ravikumar
– Barath Ravikumar, Commented Mar 12, 2013 at 3:25
You cannot start identifiers with numbers in C++, i.e. 2Darray needs to be twoDarray, etc. — Jesse Good
– Jesse Good, Commented Mar 12, 2013 at 3:28

Jesse Good · Accepted Answer · 2013-03-12 03:29:00Z

3

You could change to accept references:

void check(string (&temp2D)[100][100], string (&temp1D)[100]);

or pointers:

void check(std::string temp2D[][100], std::string temp1D[]){}

which is the same as the following just different syntax:

void check(std::string (*temp2D)[100], std::string* temp1D){}

Also, you cannot start variable names with numbers, 2Darray, etc. is a compiler error.

Here is a full working example:

#include <string>

void check(std::string (&temp2D)[100][100], std::string (&temp1D)[100]){}

int main()
{
    std::string twoDarray[100][100];
    std::string oneDarray[100];
    check(twoDarray,oneDarray);
}

answered Mar 12, 2013 at 3:29

Jesse Good

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