Just looking for python code that can turn all chars from a normal string(all english alphbetic letters) to ascii hex in python. I'm not sure if I'm asking this in the wrong way because i've been searching for this but can't seem to find this.
I must just be passing over the answer, but i would love some help.
Just to clarify, from 'Hell' to '\x48\x65\x6c\x6c'
I suppose ''.join(r'\x{02:x}'.format(ord(c)) for c in mystring) would do the trick...
>>> mystring = "Hello World"
>>> print ''.join(r'\x{02:x}'.format(ord(c)) for c in mystring)
\x48\x65\x6c\x6c\x6f\x20\x57\x6f\x72\x6c\x64
''.join([r'\x%x'%ord(c) for c in mystring]) will probably work back to python2.4 at least ... (whenever list-comps were introduced) -- And in general, from a performance standpoint, it is always better to join a list comprehension compared to a generator expression in Cpython ... So there's no harm in using that other than being a somewhat ugly style.
Based on Jon Clements's answer, try the codes on python3.7. I have the error like this:
>>> s = '1234'
>>> hexlify(s)
Traceback (most recent call last):
File "<pyshell#13>", line 1, in <module>
hexlify(s)
TypeError: a bytes-like object is required, not 'str'
Solved by the following codes:
>>> str = '1234'.encode()
>>> hexlify(str).decode()
'31323334'
Something like:
>>> s = '123456'
>>> from binascii import hexlify
>>> hexlify(s)
'313233343536'
Try:
" ".join([hex(ord(x)) for x in myString])
Starting from Python 3.5 you can use hex method to convert string to hex values (resulting in a string):
str = '1234'
str.encode().hex()
# '31323334'
Knowing that it's possible to resolve it in yet another way:
str = '1234'
hexed = str.encode().hex()
hex_values = [hexed[i:i+2] for i in range(0, len(hexed), 2)] # every 2 chars
delim = r'\x'
res = delim + delim.join(hex_values)
print(res)
# '\x31\x32\x33\x34'
Note:
You can omit encode() method if you define your string as bytes: str = b'1234'.
