How can we find the Duplicate values in array using php?

Question

I would like to know, how can we detect the duplicate entries in array...

Something like

$array = array("192.168.1.1", "192.168.2.1","192.168.3.1","192.168.4.1","192.168.2.1","192.168.2.1","192.168.10.1","192.168.2.1","192.168.11.1","192.168.1.4") ;

I want to get the number of Duplicity used in array (C class unique). like this

192.168.1.1 = unique
192.168.2.1 = Duplicate
192.168.3.1 = unique
192.168.4.1 = unique
192.168.2.1 = Duplicate
192.168.2.1 = Duplicate
192.168.10.1 = unique
192.168.2.1 = Duplicate
192.168.11.1 = unique
192.168.1.4 = Duplicate (Modified)

I tried this code like this style

$array2 = array() ;

foreach($array as $list ){

$ips = $list;

$ip = explode(".",$ips);

$rawip = $ip[0].".".$ip[1].".".$ip[2] ;

array_push($array2,$rawip);

}

but i am unable to set the data in right manner and also unable to make the loop for matching the data.

modified values

Thanks

SAM

possible duplicate of How to detect duplicate values in PHP array? — Dipesh Parmar
– Dipesh Parmar, Commented Mar 4, 2013 at 10:33

Prasanth Bendra · Accepted Answer · 2013-03-04 10:39:19Z

4

Try this : this will give you the count of each value

$array = array("192.168.1.1", "192.168.2.1","192.168.3.1","192.168.4.1","192.168.2.1","192.168.2.1","192.168.10.1","192.168.2.1","192.168.11.1") ;

$cnt_array = array_count_values($array)

echo "<pre>"; 
print_r($cnt_array);

$res = array();
foreach($cnt_array as $key=>$val){
   if($val == 1){
      $res[$key] = 'unique';
   }
   else{
      $res[$key] = 'duplicate';
   }
}

echo "<pre>";
print_r($res);

edited Mar 4, 2013 at 10:39

answered Mar 4, 2013 at 10:33

Prasanth Bendra

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2 Comments

Sam Over a year ago

Please see the updated question. i said the duplicate c' class

Raymond Over a year ago

You forgot to put semicolon in the end $cnt_array = array_count_values($array);

Devang Rathod · Accepted Answer · 2013-03-04 10:33:02Z

0

use array_unique($array) function. it will give you below output.

Array
(
    [0] => 192.168.1.1
    [1] => 192.168.2.1
    [2] => 192.168.3.1
    [3] => 192.168.4.1
    [6] => 192.168.10.1
    [8] => 192.168.11.1
)

And total duplicate count must be :

array_count_values($array)

answered Mar 4, 2013 at 10:33

Devang Rathod

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1 Comment

Sam Over a year ago

Please see the updated question. i said the duplicate c' class

Tapas Pal · Accepted Answer · 2013-03-04 10:34:21Z

0

Try this, hope it'll work

$FinalArray=array();
$arrayLen=count($array);
for($i=0; $i<$arrayLen;  $i++)
{
    if(!in_array($array[$i],$FinalArray))
        $FinalArray[]=$array[$i];
}

Now in $FinalArray you got all the unique ip

answered Mar 4, 2013 at 10:34

Tapas Pal

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1 Comment

Sam Over a year ago

Please see the updated question. i said the duplicate c' class

fantaghirocco · Accepted Answer · 2016-08-01 10:12:07Z

0

Try this:

for ($i = 0; $i < count($array); $i++) 
    for ($j = $i + 1; $j < count($array); $j++)
        if ($array[$i] == $array[$j])
            echo  $array[$i];

edited Aug 1, 2016 at 10:12

fantaghirocco

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answered Aug 1, 2016 at 9:49

user2918630

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Comments

Bhupesh · Accepted Answer · 2017-05-30 05:54:39Z

0

use in_array() function to check value is or not in array

<?php
$output ='';
$array = array(0, 1, 1, 2, 2, 3, 3);
$isArraycheckedvalue = array();
for ($i=0; $i < sizeof($array); $i++) 
{
    $eachArrayValue = $array[$i];
    if(! in_array($eachArrayValue, $isArraycheckedvalue)) 
    {
        $isArraycheckedvalue[] = $eachArrayValue;
        $output .= $eachArrayValue. " Repated no <br/>";      
    }
    else
    {
        $isArraycheckedvalue[] = $eachArrayValue;
        $output .= $eachArrayValue. " Repated  yes <br/>";
    }
}
echo $output;
?>

answered May 30, 2017 at 5:54

Bhupesh

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Comments

HiDeoo · Accepted Answer · 2016-07-27 06:50:42Z

-1

find the Duplicate values in array using php

function array_repeat($arr){
    if(!is_array($arr))
        return $arr;
    $arr1 = array_unique($arr);
    $arr3 = array_diff_key($arr,$arr1);
    return array_unique($arr3);
}

edited Jul 27, 2016 at 6:50

HiDeoo

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answered Jul 27, 2016 at 4:12

Shelly Chen

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