This is an extension to my previous question but in a reversed order: that is, with string -t-c-over----, is there a way to generate a binary list that all valid letters have 1 and hyphens have 0:
[0, 1, 0, 1, 0, 1, 1, 1, 1, 0, 0, 0, 0]
- t - c - o v e r - - - -
I feel sorry for the back and forth but it has to go like this.
>>> s = '-t-c-over----'
>>> lst = [0 if i == '-' else 1 for i in s]
>>> print lst
[0, 1, 0, 1, 0, 1, 1, 1, 1, 0, 0, 0, 0]
The list comp checks if a letter is '-' - if it is, it puts a 0 in the list, otherwise it puts a 1 in.
;)You can use this
string = "-t-c-over----"
[0 if i == "-" else 1 for i in string]
Output: [0, 1, 0, 1, 0, 1, 1, 1, 1, 0, 0, 0, 0]
Another option is use a lambda function and a map function.
s = '-t-c-over----'
output = map(lambda x: 0 if x == '-' else 1, s)
Edit: Apparently this doesn't work in Python 3.2 so the practical solution would be something like this.
s = '-t-c-over----'
output = [0 if x == '-' else 1 for x in s]
