How to Construct JSON string django view?

Question

I want to construct json like this in the django view:

{
    "Skills": [
        {
            "Name": "Java",
            "Value": "Java"
        },
        {
            "Name": "J2ee",
            "Value": "J2ee"
        },
        {
            "Name": "Python",
            "Value": "Python"
        },
        {
            "Name": "Django",
            "Value": "Django"
        }
    ]
}

The python simplejson does not create it like the above, any suggestions please. Basically I am sending response to the select2 tag. I am invoking the view method from the Jquery ajax ..

def populateSkills(request):
    print "Inside Populate Skills"
    preload_data = '{"Skills":[{"Name":"Java","Value":"Java"},{"Name":"J2ee","Value":"J2ee"},{"Name":"Python","Value":"Python"},{"Name":"Django","Value":"Django"}]}'
    return HttpResponse(simplejson.dumps(preload_data), content_type="application/json")

I have the preload_data hard-coded as I could not construct it. So how do I construct it? is there a JSONObject to do it?

May you want to explain the problem in more detail. What JSON do you get? What is input? — Rohan
– Rohan, Commented Feb 22, 2013 at 9:29
preload_data is string, not dictionary with nested structures. So dumps() will return this string as JSON string. — kolen
– kolen, Commented Feb 22, 2013 at 9:46
i.e. you already have some data encoded as json inside preload_data string. You are trying to encode it again using dumps(). If you already have json-encoded string, you can just output it: return HttpResponse(preload_data, content_type="application/json"). — kolen
– kolen, Commented Feb 22, 2013 at 9:50

Lukasz Koziara · Accepted Answer · 2013-02-22 09:46:29Z

2

Using simplejson:

import simplejson
simplejson.dumps({'Skills': [{'Name': 'Java', 'Value': 'Java'}, {'Name': 'J2ee', 'Value': 'J2ee'}, {'Name': 'Python', 'Value': 'Python'}, {'Name': 'Django', 'Value': 'Django'}] })

answered Feb 22, 2013 at 9:46

Lukasz Koziara

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