Java declaring a String array in method invocation

Question

I'm trying to declare a String array within a method invocation, like so:

if (emailYaml.keySet().containsAll(new String[]{"mailto","subject","text"}))

I'm not entirely sure if this is the best approach in any case (i'm pretty new to programming), but in any case Eclipse tells me:

The method containsAll(Collection<?>) in the type Set<String> is not applicable for the arguments (String[])

Could anyone help with a solution?

Many thanks

sp00m · Accepted Answer · 2013-02-21 15:50:21Z

4

An array isn't a subtype of Collection. Convert it to a List for example, before passing it to containsAll:

.containsAll(Arrays.asList(new String[] {"mailto", "subject", "text"}))

Or even simplier, since asList takes a vararg as parameter:

.containsAll(Arrays.asList("mailto", "subject", "text"))

answered Feb 21, 2013 at 15:50

sp00m

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Comments

PermGenError · Accepted Answer · 2013-02-21 15:48:45Z

0

containsAll() expects a Collection and you are passing an array, thus your compiler complains.

if (emailYaml.keySet().containsAll(Arrays.asList(new String[]
  {"mailto","subject","text"})))

answered Feb 21, 2013 at 15:48

PermGenError

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easier: if (emailYaml.keySet().containsAll(Arrays.asList("mailto","subject","text")))

user000001 · Accepted Answer · 2013-02-21 15:54:50Z

0

Contains all accepts a collection.

From the docs:

containsAll(Collection<?> c)

Try this insead:

if (emailYaml.keySet().containsAll(Arrays.asList("mailto","subject","text"))

answered Feb 21, 2013 at 15:48

user000001

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