Identical string return FALSE with '==' in Python, why?

Question

The data string is receive through a socket connexion. When receiving the first example where action variable would = 'IDENTIFY', it works. But when receiving the second example where action variable would = 'MSG' it does not compare.

And the most bizarre thing, when I use Telnet instead of my socket client both are being compare successfully. But the string are the same... Is there a possibility that the string are not encode in the same way? How can I know?

data example:

data = 'IDENTIFY 54143'
or
data = 'MSG allo'

action = data.partition(' ')[0]
if action == "MSG":
    self.sendMessage(data)
elif action == "IDENTIFY":  
    self.sendIdentify(data)
else:
    print "false"

Alex Martelli · Accepted Answer · 2009-09-29 14:50:26Z

5

Can't reproduce your problem. To debug it, print or log the repr() of data and action: this will likely show you the cause (probably some non-visible binary byte has snuck into data, based on how you obtained it [[which you don't show us]] and hence into action).

answered Sep 29, 2009 at 14:50

Alex Martelli

887k175 gold badges1.3k silver badges1.4k bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

plehoux Over a year ago

'\x00MSG Allo' that's what I get. I will try to find how to escape it. Tks a lot! Tks since i'm new to python I did not know repr().

SilentGhost Over a year ago

@plehoux: you can just lstrip this character.

Collectives™ on Stack Overflow

Identical string return FALSE with '==' in Python, why?

1 Answer 1

2 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related