How do I pass 2 PHP variables in a javascript function?
This one is working
echo '<button onClick = "count('.$increment.')">'.$counter.' </button>';
but when i do this
echo '<button onClick = "count('.$increment.','.$pass.')">'.$counter.' </button>';
it does not work, what is the problem?
By the way these are the variables:
$increment=5;
$pass="sdfgd";
Try this dude......
<button onClick = "count('<?php echo $increment ?>','<?php echo $pass ?>')"><?php echo $counter ?></button>
echo '<button onClick = "count('.$increment.',\''.$pass.'\')">'.$counter.' </button>';
If $pass contains exactly "sdfgd" and with exactly I mean double quotes includes, this isn't a valid statement anymore, because your parser will find double quotes "too early" and them will close the onClick event attribute
After variable expansion:
echo '<button onClick = "count('5','"sdfgd"')">'.$counter.' </button>';
-------------------------------------^
Take a look to the arrow
However, if you use a tool like firebug (if you run firefox), you can debug your code easily
The generated HTML code should look like this:
<button onClick = "count(5,sdfgd)">5 </button>
The variable sdfgd is most likely undefined, therefore undefined gets passed to your function.
If you want to pass a string you have to use quotes, so that the generated HTML looks like this:
<button onClick = "count(5,'sdfgd')">5 </button>
