Java Regular Expression Issue

Question

The following exception is thrown when this [0-9]+_[0-9]+_[0-9]+(_[0-9]+){0,1} regex is used.

Caused by: java.util.regex.PatternSyntaxException: Unclosed counted closure near index 31
[0-9]+_[0-9]+_[0-9]+(_[0-9]+){0
                               ^
    at java.util.regex.Pattern.error(Pattern.java:1713)
    at java.util.regex.Pattern.closure(Pattern.java:2759)
    at java.util.regex.Pattern.group0(Pattern.java:2537)
    at java.util.regex.Pattern.sequence(Pattern.java:1806)
    at java.util.regex.Pattern.expr(Pattern.java:1752)
    at java.util.regex.Pattern.compile(Pattern.java:1460)
    at java.util.regex.Pattern.<init>(Pattern.java:1133)
    at java.util.regex.Pattern.compile(Pattern.java:823)

I am reading this from a XML File.

I use Java Standard Pattern.compile and Pattern.matcher in the code. — shazin
– shazin, Commented Feb 12, 2013 at 13:34

epoch · Accepted Answer · 2013-02-12 13:38:04Z

3

You probably want this:

[0-9]+_[0-9]+_[0-9]+(_[0-9]+)?

edited Feb 12, 2013 at 13:38

answered Feb 12, 2013 at 13:17

epoch

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2 Comments

shazin Over a year ago

But the same pattern works in this regexplanet.com/advanced/java/index.html

epoch Over a year ago

can you give some examples of what you need to match? Your supplied regex compiles fine, you may have an extra character somewhere in your string. post the code :)

mkczyk · Accepted Answer · 2018-03-01 15:14:29Z

0

You have to escape commas with backslash:

[0-9]+_[0-9]+_[0-9]+(_[0-9]+){0\,1}

answered Mar 1, 2018 at 15:14

mkczyk

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1 Comment

Geert-Jan Hut Over a year ago

You don't have to escape comma's with backslash in Java regex expressions. An expression like this works: "^(\\d+\\.){0,2}\\d+$". See also the discussion on backslash, escapes and quoting in the Javadoc.

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