I'm a Python beginner. I'd like to find <(.+?)> from a string, and replace it with [\1]. For example,
string_input = '<age>'
string_output = '[age]'
I tried,
import re
string = '<age>'
re.sub('<.+?>, '[' + \1 + ']', string)
But it failed.
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use \g<> is recommended as it can avoid ambiguity like '\12\3'.Wei Zhong– Wei Zhong2015-09-10 18:54:34 +00:00Commented Sep 10, 2015 at 18:54
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4 Answers
>>> re.sub('<(.+)>', '[\\1]', '<age>')
'[age]'
Double \\ is used to escaping the \, or else \1 will be recognised as \x01.
Brackets () are used as a capturing group.
You can use multiple capturing groups like this:
>>> re.sub('<(.+)=+(.*)>', '[\\1: \\2]', '<age=5>')
'[age: 5]'
Comments
You best access the capturing group by using \g<>, so since you only have one capturing group, you use \g<1>.
In [1]: re.sub(r'<(.+?)>', '[\g<1>]', '<age>')
Out[1]: '[age]'
The advantage of using \g<> is that you can also give names to your capturing groups and then access them by the names again, for example:
In [2]: re.sub(r'<(?P<content>.+?)>', '[\g<content>]', '<age>')
Out[2]: '[age]'
Comments
re.sub("<([^>]+)>", "[\g<1>]", s)
Comments
As Alex L says, but you don't need the ? character:
import re
re.sub('<(.+)>', '[\\1]', '<age>')
