I have a string like this:
http://x.com/xyz/2013/01/16/zz/040800.php
I want to get two strings from that, like this:
2013-01-16 <-- string 1
04:08:00 <-- string 2
How can I do that?
2 Answers
You can use regulax expressions. Here is a sample solution:
var parts = (/.com\/[^\/]+\/(\d+)\/(\d+)\/(\d+)/g).exec('http://x.com/xyz/2013/01/16/zz/040800.php'),
result = parts[1] + '-' + parts[2] + '-' + parts[3]; //"2013-01-16"
This will work if your domain is .com and you have just one extra parameter before the date.
Let me explain you the regular expression:
/ //starts the regular expression
.com //matches .com
\/ //matches /
[^\/]+ //matches anything except /
\/ //matches a single /
(\d+) //matches more digits (one or more)
\/ //matches /
(\d+) //matches more digits (one or more)
\/ //matches /
(\d+) //matches more digits (one or more)
/ //ends the regular expression
Here is how you can extract the whole data:
var parts = (/.com\/[^\/]+\/(\d+)\/(\d+)\/(\d+)\/[^\/]+\/(\d+)/g).exec('http://x.com/xyz/2013/01/16/zz/040800.php'),
part2 = parts[4];
parts[1] + '-' + parts[2] + '-' + parts[3]; //"2013-01-16"
part2[0] + part2[1] + ':' + part2[2] + part2[3] + ':' + part2[4] + part2[5];
1 Comment
Minko Gechev
Just updated my answer and included information about that how you can extract the second value too :-)
If the url is always of the same format, do this
var string = 'http://x.com/xyz/2013/01/16/zz/040800.php';
var parts = string.split('/');
var string1 = parts[4] +'-' +parts[5] +"-" +parts[6];
var string2 = parts[8][0]+parts[8][1] +":" +parts[8][2]+parts[8][3] +":" +parts[8][4]+parts[8][5];
alert(string1);
alert(string2);
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