conditional check of nested array

Question

I've got the following snippet to dump some info on the screen:

for ($i=0; $i < 60; $i++) {
  echo 'output: '.$array[$i]['options'][0]."<br />";
  echo 'output: '.$array[$i]['options'][4]."<br />";
}

which outputs the following:

output: Lorem ipsum
output: 1
output: dolor sit amet
output: 1
output: consectetur adipiscing elit
output: 0

How do I wrap the echo statements in a conditional, so only when ['options'][4] == '1' it will run?

if ($array[$i]['options'][4] == '1') {
...
}

Doesn't work and returns nothing, set it to == '0' and you'll get everything. I've tried assigning it to a variable first, tried converting to ints first, but they all seem to return 0, while an echo displays the value.

Got night-time creative with foreach loops, trying to drill down to the items, only resulting in loss of keys where values were still properly read. Its probably something simple, but its been ages since I dabbled with php and arrays.

if $array[$i]['options'][4] == '1' does not work, var_dump it first and see what does it contain. — Shiplu Mokaddim
– Shiplu Mokaddim, Commented Jan 16, 2013 at 7:46
Well last night I could have sworn it didn't, but now it did, must have made some typos.. — jbokkers
– jbokkers, Commented Jan 16, 2013 at 8:00

Shiplu Mokaddim · Accepted Answer · 2013-01-16 07:42:16Z

2

Wrap it with a simple if. But why use txt? shouldn't you use options?

if(isset($array[$i]['options'][4]) and $array[$i]['options'][4]==1){
  echo 'output: '.$array[$i]['options'][0]."<br />";
  echo 'output: '.$array[$i]['options'][4]."<br />";
}

answered Jan 16, 2013 at 7:42

Shiplu Mokaddim

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1 Comment

jbokkers Over a year ago

Thanks should have asked this last night instead of wasting nightly hours being blind and get a SO within minutes! The ['txt'] vs ['options'] was a typo in making it more SO friendly.

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