After reading the post here, I tried to get the value by regex as below:
var myString = "<a href='/search.html?id=HDJ&area=ASD&estate=JKG&ppt=3'></a>";
var myRegexp = /&estate=(.*?)(?:\s|$)/g;
var match = myRegexp.exec(myString);
match[1]
The result was JKG&propertytype=3'></a>, but I only want JKG. Strictly speaking I want the value between &estate= and &ppt Could someone suggest how to do that?
Thanks
A Regular Expression:
/&estate=(.*?)&ppt=/g
Note: I wouldn't recommend using regular expressions to parse query strings. It's brittle. Consider if the variables in the query string change order. If that can be the case, I recommend reading - Parse query string in JavaScript.
do:
var myString = "<a href='/search.html?id=HDJ&area=ASD&estate=JKG&ppt=3'></a>";
var myRegexp = /estate=(.*)&ppt=/g;
var match = myRegexp.exec(myString);
console.log( match[1] );
/estate=(.*)&ppt=/g; and /estate=(.*?)&ppt=/g;?
* = 0 or more times and ? = 0 or 1 times Therefore, having ? is redundant for *? To verify, enter and test your regex here.
*? means a non-greedy 0 or more match.group. So then, (RegExp?) is non-greedy, while as you say (*?) is non-greedy 0 or more times, I certainly agree. However, I don't see a logical difference in your regex requiring it to be greedy to function correctly. Perchance when your regex is part of another group, then it sings it's use. Am I mistaken that it needs to be greedy as it stands?If only the solution is important then you can use the following:
var myString = "<a href='/search.html?id=HDJ&area=ASD&estate=JKG&ppt=3'></a>";
var indx1 = mystring.indexOf("&estate=") + 8;
var indx2 = mystring.indexOf("&ppt");
var neededString = mystring.substring(indx1, indx2);
Just exclude ampersands from the selection:
var myRegexp = /&estate=([^&]+)/g;
You might want to change it to this, in case estate is the first parameter:
var myRegexp = /[\?&]estate=([^&]+)/g;
Based on your result value, just split it at the ampersand, no new or alternate regex required.
JavaScript:
var myString = "<a href='/search.html?id=HDJ&area=ASD&estate=JKG&ppt=3'></a>";
var myRegexp = /&estate=(.*?)(?:\s|$)/g;
var match = myRegexp.exec(myString);
var value = match[1].split('&')[0];
alert( value );
