Function property and prototype - Javascript

Question

What is this?

en4.activity.like(c)

Is this a function like() of property 'activity' of object en4?

I need to re-write the function but in the same format and I'm confused.

what is en4? Is this an instance or an object (direct instance of an object)? — Luca Rainone
– Luca Rainone, Commented Dec 30, 2012 at 22:01

ThiefMaster · Accepted Answer · 2012-12-30 21:56:08Z

3

This would do the job:

var en4 = {
    activity: {
        like: function(c) {

        }
    }
};

In case en4 already exists and also has a property activity you'd do it like this:

en4.activity.like = function(c) {
    ...
};

If that property also doesn't exist:

en4.activity = {
    like: function(c) {

    }
};

Since you just have a single object there is most likely no need to involve prototypes at all.

answered Dec 30, 2012 at 21:56

ThiefMaster

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2 Comments

If en4 exists but has no property activity, does the last example still work?

Nope, in this case it would have to be created first, too.

David G · Accepted Answer · 2012-12-30 21:57:53Z

1

Try this:

function nsp() {
    this.activity = {
        like: function(a) {}
    };
}

var en4 = new nsp();

en4.activity.like(c);

answered Dec 30, 2012 at 21:57

David G

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