Using replace() function to replace multiple texts(strings) at once in Python

Question

Here's my code:

start_j = raw_input('Enter a name: ')
start_j = start.replace("A", "J")
start_j = start.replace("B", "J")
start_j = start.replace("C", "J")
print "Your name is " + start_j

Is there anyway to put all the alphabets in one list so that I wouldn't have to repeat the same process again and again until I reach letter "Z" I tried using loops, but I still can't seem to get the right way to do it.

Here's a scenario: The user will be prompted to input a name. If the name contains a letter other than "J", it will be automatically replaced using the replace() function. Hence it will print out the input starting with J

Here's an example:

site = raw_input('Enter your website: ')
site = site.replace("http://", "")
site = site.replace("https://", "")
site = site.replace("ftp://", "")
print "Your website is: " + site

An expected input would be http://www.google.com So the expected out would become:

Enter your website: http://www.google.com
Your website is: www.google.com

I'm looking for a way to put "http://", "https://", "ftp://" all in one list so I wouldn't have to enter

site = site.replace("something", "something)

many times

Oh wow, your edit really changes the question a lot. Your original question was far from clear enough. — Mark Byers
– Mark Byers, Commented Dec 24, 2012 at 0:26
Sorry if I was unclear. It's 5 am in the morning and I haven't slept in a while. — Max Wayne
– Max Wayne, Commented Dec 24, 2012 at 0:29
@MarkByers, It seems like the same question to me before vs after the sample/example/illustration. Can you help me figure out what or how i was reading the question wrong before the sample if you understood it differently? I ask this because i am working on bettering my requirement discerning skills, to better read a given requirement document or may be even trying to look at them from a different perspective. This may sound weird but i promise you it is not and it really matters in work env and especially for me. ty. — Code Man
– Code Man, Commented Oct 28, 2021 at 17:34

Blender · Accepted Answer · 2012-12-24 00:18:31Z

4

You could use a regex to replace all of the letters at once:

>>> import re
>>> re.sub(r'[A-Z]', 'J', 'This Is A Test Name')
'Jhis Js J Jest Jame'

(After edit): You can use .startswith() and string slicing:

>>> name = 'A Name'
>>> 
>>> if not name.startswith('J'):
...     name = 'J' + name[1:]
... 
>>> name
'J Name'

Although I'm not sure why you'd even need to check with .startswith(). Either way, the result will be the same.

edited Dec 24, 2012 at 0:18

answered Dec 24, 2012 at 0:12

Blender

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Comments

Mark Byers · Accepted Answer · 2012-12-24 00:28:36Z

3

You can use this:

remove_from_start = ["http://", "https://", "ftp://"]
for s in remove_from_start:
    if site.startswith(s):
        site = site[len(s):]
        break

Or a regular expression based solution:

import re
regex = '^(https?|ftp)://'
site = re.sub(regex, '', site)

edited Dec 24, 2012 at 0:28

answered Dec 24, 2012 at 0:10

Mark Byers

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2 Comments

Max Wayne Over a year ago

start_j is variable that requires an input which would be the name. If any name starts with a letter other than "J", it will be automatically replaced.

Mark Byers Over a year ago

@MaxWayne: Starts with? replace examines the entire string, not just the first character.

Aamir Rind · Accepted Answer · 2012-12-24 00:33:59Z

1

import re

site = raw_input('Enter your website: ')
# input http://www.google.com or https://www.google.com or ftp://www.google.com
site = re.sub('^(?:https?|ftp)://', '', site)
print "Your website is: " + site

answered Dec 24, 2012 at 0:33

Aamir Rind

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Comments

Ashwini Chaudhary · Accepted Answer · 2012-12-24 01:51:27Z

0

use a dictionary:

In [100]: import string

In [101]: dic=dict.fromkeys(string.ascii_uppercase,"J")

In [104]: start_j = raw_input('Enter a name: ')
Enter a name: AaBbCc

In [105]: "".join(dic.get(x,x) for x in start_j)
Out[105]: 'JaJbJc'

Edit:

In [124]: dic={"https:":"","http:":"","ftp:":""}

In [125]: strs="http://www.google.com"

In [126]: "".join(dic.get(x,x) for x in strs.split("//"))
Out[126]: 'www.google.com'

edited Dec 24, 2012 at 1:51

answered Dec 24, 2012 at 0:12

Ashwini Chaudhary

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h11 · Accepted Answer · 2012-12-24 03:32:37Z

0

use re, dict and lambda:

import re
replacte_to = {
    "http://": "",
    "https://": "",
    "ftp://": "",
}
re.sub("^(ht|f)tps?://", lambda match: replacte_to[match.group(0)], YOUR_INPUT_STRING)

answered Dec 24, 2012 at 3:32

h11

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