Having troubles with awk. Basically what I'm trying to do is search for this particular string in the file. And then print the 3rd element of that line.
Here's what I did:
awk -F' / ' '$1=="$log"{print $3}' schedlist
For some reason that won't work but if I do this:
awk -F' / ' '$1=="20121213-20:58:53"{print $3}' schedlist
The code works. But I need to let the user input log name.
You need to use the -v option to pass a shell variable into awk, like this:
awk -v tstamp="$log" -F' / ' '$1==tstamp{print $3}' schedlist
(Updated the variable name to tstamp (as mentioned in the comments), because log clashes with the awk built-in function log.)
awk -v tstamp="$log" -F' / ' '$1==tstamp{print $3}' schedlistYou have several options. Use a variable ( either with -v or simply as an assignment, but you cannot name it "log", because that is an awk function):
awk -F' / ' '$1 == s {print $3}' s="$log" schedlist
quote your script differently:
awk -F' / ' '$1 == "'"$log"'" { print $3}' schedlist
