How to make custom array in python django

Question

I have this list of dict

{"FieldFlags": "0", "FieldNameAlt": "Please forgive me", "FieldName": "field1", "FieldType": "Text", "FieldJustification": "Left", "FieldValue": "test"},
 {"FieldJustification": "Left", "FieldNameAlt": "Please forgive me", "FieldName": "min_speed", "FieldType": "Text", "FieldFlags": "0"},
 {"FieldJustification": "Left", "FieldNameAlt": "Please forgive me", "FieldName": "avg_speed", "FieldType": "Text", "FieldFlags": "0"}, 
 {"FieldJustification": "Left", "FieldNameAlt": "Please forgive me", "FieldName": "lowest_speed", "FieldType": "Text", "FieldFlags": "0"},
 {"FieldJustification": "Left", "FieldNameAlt": "Please forgive me", "FieldName": "air", "FieldType": "Text", "FieldFlags": "0"}, 
 {"FieldJustification": "Left", "FieldNameAlt": "Please forgive me", "FieldName": "slope", "FieldType": "Text", "FieldFlags": "0"}]

For my purpose i need to convert this array to something like

fields = [('field1','test'),('min_speed',''),('avg_speed','')..]

So basically i want the tuple of (FiedName,FieldValue)

If fieldValue is not there , then it should be displayed as empty

How can i convert that

Jesse the Game · Accepted Answer · 2012-12-03 01:54:33Z

4

fields = [(d['FieldName'], d.get('FieldValue', '')) for d in your_list]

answered Dec 3, 2012 at 1:54

Jesse the Game

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1 Comment

Jesse the Game Over a year ago

d is just a name for the values in your_list while iterating over them. It could have been anything, but I chose d as we're iterating over a list of d ictionaries.

Krotton · Accepted Answer · 2012-12-03 01:59:31Z

0

You can also use map():

fields = map(lambda d: (d['FieldName'], d.get('FieldValue', '')), your_list)

answered Dec 3, 2012 at 1:59

Krotton

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