PHP - regexp to split URLs

Question

I have a text with "a href" and "[link]" links. I want to preg_split this text and have array where on [i] I can found links

Example:

My text <a href="www.example.com">text</a> this continues [link=http://www.second.com]link[/link]

=>

[0] My text
[1] <a href="www.example.com">text</a>
[2] this continues
[3] [link=http://www.second.com]link[/link]

How should I wrote my regexp?

Don't parse HTML with regular expressions. Use the DOM module that comes with PHP. Regular expressions are not always the tool to use, even if the problem involves text. — Andy Lester
– Andy Lester, Commented Dec 2, 2012 at 15:40

Oliver Atkinson · Accepted Answer · 2012-12-02 12:46:21Z

1

(.+)(\<a.+\/a>)(.+)(\[link.+\/link])

produces

Match groups:
1.  My text
2.  <a href="www.example.com">text</a>
3.  this continues
4.  [link=http://www.second.com]link[/link]

http://rubular.com/r/8PEUbDX9zr

answered Dec 2, 2012 at 12:46

Oliver Atkinson

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Comments

Damien Overeem · Accepted Answer · 2012-12-02 10:09:24Z

0

Something like this i guess. Assuming everything is on the same line..

/\<a\.*[link=(.*)\].*$/i

answered Dec 2, 2012 at 10:09

Damien Overeem

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Comments

Jesperhag · Accepted Answer · 2012-12-02 10:14:47Z

0

<?php
$text = 'My text <a href="www.example.com">text</a> this continues [link=http://www.second.com]link[/link]';


preg_match_all('/(?:href="|link=)(.*?)(?:"|\])/is', $text, $links);
// $links[1] = array('link', 'link', 'link'...)
$links = $links[1]; // $links = array('link'...)
?>

Should work :)

answered Dec 2, 2012 at 10:14

Jesperhag

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3 Comments

Martin Perry Over a year ago

It returns only [0] => www.example.com

Jesperhag Over a year ago

If I copy my example straight off and run it and var_dump $links I get [0] => "www.example.com" [1] => "second.com" Sure you are using preg_match_all?

Martin Perry Over a year ago

Strange.. If I copy & paste your example, I got only what I posted... and even your output is different from what I needed

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