I have a path and I am trying to pop off everything after the last /, so 'folder' in this case, leaving the newpath as C://local/drive/folder/.
I tried to pop off the last / using pop(), but can't get the first part of the path to be the new path:
var path = C://local/drive/folder/folder
var newpath = path.split("/").pop();
var newpath = newpath[0]; //should be C://local/drive/folder/
How can I accomplish this?
Use .slice() instead of pop()
var newpath = path.split("/").slice(0, -1).join("/");
If you also need the last part, then just use .pop(), but first store the Array in a separate variable.
var parts = path.split("/");
var last = parts.pop();
var first = parts.join("/");
Now last has the last part, and first has everything before the last part.
Another solution is to use .lastIndexOf() on the string.
var idx = path.lastIndexOf("/");
var first = path.slice(0, idx);
var last = path.slice(idx + 1);
Just replace the last statement to be like that:
var path = C://local/drive/folder/folder
path.split("/").pop(); // Discard the poped element.
var newpath = path.join("/"); // It will be C://local/drive/folder
A note about Array.pop: Each time you call the pop method it will return the last element and also it will remove it from the array.
Could also use a regex:
function stripLastPiece(path) {
var matches = path.match(/^(.*\/)[^\/]+$/);
if (matches) {
return(matches[1]);
}
return(path);
}
Working example: http://jsfiddle.net/jfriend00/av7Mn/
If you want to get the first part of the array.
var firstWord = fullnamesaved.split(" ").shift();
This disregards all things after the space.
var foo = "C://local/drive/folder/folder";
foo.match(/(.+\/)[^\/]+$/);
would result in: ["C://local/drive/folder/folder", "C://local/drive/folder/"]
though i would prefer user1689607's answer
