Java Regex/Split

Question

I'm looking to split a string at the first ':', to prevent issues if the second part of the string contains a ':'. I've been looking at Regexes, but am still having some issues, can somebody give me a hand? Thanks.

Could you include an example of expected input and output?

FThompson
– FThompson

2012-12-01 21:29:43 +00:00
Commented Dec 1, 2012 at 21:29 — FThompson
– FThompson, Commented Dec 1, 2012 at 21:29

Mark Byers · Accepted Answer · 2012-12-01 21:31:26Z

10

You can use the overload of split that takes a limit parameter:

String[] result = s.split(":", 2);

answered Dec 1, 2012 at 21:31

Mark Byers

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Rohit Jain · Accepted Answer · 2012-12-01 21:37:55Z

7

You can use 2 argument String#split to specify the number of elements you want in your array obtained after split: -

String str = "rohit:jain:use:single:split";
String[] arr = str.split(":", 2);

edited Dec 1, 2012 at 21:37

answered Dec 1, 2012 at 21:31

Rohit Jain

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Viacheslav Chumushuk · Accepted Answer · 2012-12-01 22:07:27Z

1

Notice, that split uses regexps. And indexOf + substr can be much faster than split.

answered Dec 1, 2012 at 22:07

Viacheslav Chumushuk

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