I have been trying to take elements from a array and put them into a 2d array and I was wondering if there was a way to do that?
for example
h = ['H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'T']
a = Grid(3,3) #creates empty 2d array
output would be
H H H
H H H
H H T
I been doing something likes this.
for row in range(a.getHeight()):
for col in range(a.getWidth():
for i in range(len(h):
a[row][col] = h[i]
but i get this as the output:
T T T
T T T
T T T
I think I might do something like this:
hh = iter(h)
for row in range(a.getHeight()):
for col in range(a.getWidth()):
a[row][col] = next(hh)
This assumes that you declared a properly. In other words, a is NOT a list set up as follows:
a = [[None]*ncol]*nrow
That doesn't work since a would hold a bunch of references to the same inner list. Of course, your a isn't a simple list since it has getHeight and getWidth, so I assume whatever type of object it has taken care of that already.
If you're using numpy, this becomes almost trivial:
h = np.array(['H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'T'])
a = h.reshape((3,3))
use a list comprehension:
In [11]: h = ['H', 'H', 'H', 'H', 'H', 'H', 'H', 'H', 'T']
In [12]: [h[i:i+3] for i in range(0,len(h),3)]
Out[12]: [['H', 'H', 'H'], ['H', 'H', 'H'], ['H', 'H', 'T']]
Grid object which I assume is important. If a Grid object isn't necessary, then I support this solution.