Regex to capture variables in query string

Question

I want to get a specific part of the url that is between two characters for example in the link below I want to get the part between v= and &.

http://www.youtube.com/watch?v=mof-Dq3hvWs&feature=youtu.be

I do that with the following regex (?<=v=)(.*?)(?=&)

My problem is when the link does not end with the &. For example:

http://www.youtube.com/watch?v=5FlQSQuv_mg

How can I match the string in both cases?

Jason McCreary · Accepted Answer · 2012-11-16 12:39:50Z

5

Don't use a regular expression. Use parse_url() and parse_str().

$url = 'http://www.youtube.com/watch?v=mof-Dq3hvWs&feature=youtu.be';
$parts = parse_url($url);
parse_str($parts['query'], $arr);
print_r($arr);

answered Nov 16, 2012 at 12:33

Jason McCreary

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Comments

Francis Gagnon · Accepted Answer · 2012-11-16 12:35:02Z

0

What about this then?

(?<=v=)([^&]+)

answered Nov 16, 2012 at 12:35

Francis Gagnon

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