Remove duplicate values on an array with a condition in PHP

Question

I want to remove some duplicate values on an array, but there is a condition that the script has to ignore the array that contains a specific word.

Below code is adapted from PHP: in_array.

$array = array( 'STK0000100001',
                'STK0000100002',
                'STK0000100001',           //--> This should be remove
                'STK0000100001-XXXX',      //--> This should be ignored
                'STK0000100001-XXXX' );    //--> This should be ignored

$ignore_values = array('-XXXX');

if(make_unique($array, $ignore_values) > 0) {
    //ERROR HERE
}

The function to make the array unique is:

function make_unique($array, $ignore) {
    $i = 0;
    while($values = each($array))  {
        if(!in_array($values[1], $ignore)) {
            $dupes = array_keys($array, $values[1]);
            unset($dupes[0]);
            foreach($dupes as $rmv) {
                $i++;
            }            
        }
    }
    return $i;
}

I have tried to use if(!in_array(str_split($values[1]), $ignore)) ... but it just the same.

The array should become like:

STK0000100001
STK0000100002
STK0000100001-XXXX
STK0000100001-XXXX

How to do that?

mrjimoy_05 · Accepted Answer · 2012-11-09 05:48:47Z

1

Try this one, just remove the print_r(); inside the function when using in production

if(make_unique($array, $ignore_values) > 0) {
    //ERROR HERE
}

function make_unique($array, $ignore)  {
    $array_hold = $array;
    $ignore_val = array();
    $i = 0;
    foreach($array as $arr) {
        foreach($ignore as $ign) {
            if(strpos($arr, $ign)) { 
                 array_push( $ignore_val, $arr);
                 unset($array_hold[$i]);
                 break;
            }
        }
        $i++;
    }
    $unique_one = (array_unique($array_hold));
    $unique_one = array_merge($unique_one,$ignore_val);
    print_r($unique_one);

    return count($array) - count($unique_one);
}

edited Nov 9, 2012 at 5:48

mrjimoy_05

3,58810 gold badges62 silver badges98 bronze badges

answered Nov 9, 2012 at 5:07

sephoy08

1,1147 silver badges16 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

air4x · Accepted Answer · 2012-11-09 05:45:39Z

1

This should work for >= PHP 5.3.

$res = array_reduce($array, function ($res, $val) use ($ignore_values) { 
    $can_ignore = false;
    foreach ($ignore_values as $ignore_val) {
      if (substr($val, 0 - strlen($ignore_val)) == $ignore_val) {
        $can_ignore = true;
        break;
      }
    }

    if ( $can_ignore || ! in_array($val, $res)) {
      $res[] = $val;
    }
    return $res;

  }, array()
);

Otherwise

$num_of_duplicates = 0;
$res = array();
foreach ($array as $val) { 
  $can_ignore = false;
  foreach ($ignore_values as $ignore_val) {
    if (substr($val, 0 - strlen($ignore_val)) == $ignore_val) {
      $num_of_duplicates++;
      $can_ignore = true;
      break;
    }
  }
  if ( $can_ignore || ! in_array($val, $res)) {
    $res[] = $val;
  }
}

Edit: Added duplicate count to the second snippet.

edited Nov 9, 2012 at 5:45

answered Nov 9, 2012 at 5:18

air4x

5,6831 gold badge26 silver badges36 bronze badges

1 Comment

mrjimoy_05 Over a year ago

Hi, thanks for your code. It solved my problem but it's not returning any counting value to identify if there was some value removed from the array. And btw I already have the answer. Thanks again! :)

Collectives™ on Stack Overflow

Remove duplicate values on an array with a condition in PHP

2 Answers 2

Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related