Java exception error

Question

My professor asked me to do the following homework in Java, but I'm getting error while trying to execute the code.

Please take a look at the code and let me know what's causing the error? The code is saved into Reverse.java file.

package javaapplication44;
import java.util.Scanner;
public class Reverse {
    public static void main (String[] args) {
        String Fname[] = new String[4];
        Scanner s = new Scanner(System.in);
        for (int i=0; i<=4; i++) {
            System.out.println("\n Enter Something: ");
            Fname[i] = s.nextLine();
        }
        System.out.println ("*** The String has been Reversed ***");
        for (int i=4; i>0; i--) {
            System.out.println (Fname[i]);
        }
    }
}

error text:

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 4 at javaapplication44.Reverse.main(Reverse.java:14)

Md. Rizwanul Islam · Accepted Answer · 2012-11-04 10:22:16Z

3

When u take 4 elements array then u have to count less then 4 Not less than and equal 4. first loop will be conditioned i< 4

And also the second loop will be conditioned i>3

Hope it will work

answered Nov 4, 2012 at 10:22

Md. Rizwanul Islam

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1 Comment

Desert Ice Over a year ago

Second loop should be conditioned as i=3

PermGenError · Accepted Answer · 2012-11-04 10:12:51Z

1

Array indexes start from zero

change

 for (int i=0; i<=4; i++) {

to

 for (int i=0; i<4; i++) {

also, in your second for loop, start the loop from i=3

  for (int i=3; i>0; i--) {

say if your array is of length 4, the last index would be 3.

just remember this:

 LastINdexOfAnArray = Array_Length -1;

answered Nov 4, 2012 at 10:12

PermGenError

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Comments

alex · Accepted Answer · 2012-11-04 10:12:34Z

0

Change...

for (int i=0; i<=4; i++) {

...to...

for (int i=0; i<4; i++) {

You're iterating one beyond the size of your array, getting the ArrayIndexOutOfBoundsException exception.

You also need to account for this in your second loop.

answered Nov 4, 2012 at 10:12

alex

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