Using PHP variable in header function

Question

I am trying to incorporate a variable within a PHP header function and it doesn't seem to be working, it shows the actual variable in the address bar or just loads a blank screen. I appreciate your help with this.

The code as follows

header('Location: http://'.$soft_url/main');

Is that your actual code? That won't work, because there's a syntax error in it. — andrewsi
– andrewsi, Commented Oct 25, 2012 at 14:27

CodePB · Accepted Answer · 2012-10-25 14:28:03Z

4

That code is formatted wrong.

header('Location: http://'.$soft_url.'/main');

might solve your issue

answered Oct 25, 2012 at 14:28

CodePB

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7 Comments

tadman Over a year ago

Why use single quotes and then go through all the trouble of gluing multiple strings together when double-quotes should do this for you automatically?

FabianoLothor Over a year ago

No need, PHP will take longer to concatenate.

andrewsi Over a year ago

@tadman - I tend to explicitly concatenate things; I find it makes the code a lot easier to read.

FabianoLothor Over a year ago

Wrong Single quotes are more efficient when you're not adding variables in the middle of the string.

Marc B Over a year ago

@andrewsi: any decent code editor can properly colorize php variables, no matter where they are.

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Nikolaos Dimopoulos · Accepted Answer · 2012-10-25 14:27:45Z

1

Try this:

header('Location: http://' . $soft_url . '/main');

answered Oct 25, 2012 at 14:27

Nikolaos Dimopoulos

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Comments

FabianoLothor · Accepted Answer · 2012-10-25 14:30:31Z

1

Try this:

header("Location: http://$soft_url/main");

answered Oct 25, 2012 at 14:30

FabianoLothor

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